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%========================开始提取加噪信号的各类特征值================================ for n=1:1:50;     m=n*Ns;     x=(n-1)*Ns; for i=x+1:m;          %提取加噪信号'signal_with_noise=y+noise'的前256个元素，抽取50次     y0(i)=signal_with_noise(i); ...

VHDL编写的4选一数据选择器 entity mux41a is        port(a,b:in std_logic;                s1,s2,s3,s4:in std_logic;            &nbs ...

Many times I have been asked to explain “ briefl y ” how SDH, SONET, and the OTN “ exactly ” work. The questions came mainly from new colleagues, stu- dents, and users of these technologies, personally or via the usenet newsgroup comp.dcom.sdh - sonet. I could have referred them to the standards ...

function y=lagr(x0,y0,x) %x0,y0为节点 %x是插值点 n=length(x0); m=length(x); for i=1:m z=x(i); s=0.0; for k=1:n p=1.0; for j=1:n if j~=k p=p*(z-x0(j))/(x0(k)-x0(j)); end end s=p*y0(k)+s; end y(i)=s; end

My association with the theory of controls in continuous time started during my studies at the Indian Institute of Technology, Kharagpur, India, in 1974 as an undergraduate student in the Controls and Power program. The initial introduction by Professors Kesavamurthy, Y. P. Singh, and Rajagopalan la ...

#include<stdio.h> #define TREEMAX 100 typedef struct  BT { char data; BT *lchild; BT *rchild; }BT; BT *CreateTree(); void Preorder(BT *T); void Postorder(BT *T); void Inorder(BT *T); void Leafnum(BT *T); void Nodenum(BT *T); int TreeDepth(BT *T); int count=0; void main() { BT *T=NULL; char ...

#include <stdio.h> #include <stdlib.h> #define SMAX 100 typedef struct SPNode { int i,j,v; }SPNode; struct sparmatrix { int rows,cols,terms; SPNode data [SMAX]; }; sparmatrix CreateSparmatrix() { sparmatrix A; printf("\n\t\t请输入稀疏矩阵的行数，列数和非零元素个数（用逗号隔开）:"); scanf("%d, ...

某疾病发生率y‰和年龄段x（每五年为一段，例如0~5岁为第一段..）

第一种边界条件下的三次样条插值问题（高斯消元法） 题目 计算方法上机实习题目（二） ——第一种边界条件下的三次样条插值问题（高斯消元法） 已知直升飞机旋转机翼外形曲线轮廓线上的某些型值点（见表）及端点处的一阶导数值 y' (x ) = 1.86548, y' (x ) = -0.046115 ...

x=[1,2,0,-1,3,2];h=[1,-1,1]; y1=x*h(1); y2=x*h(2); y3=x*h(3); Y1=[0,0,y1]; Y2=[0,y2,0]; Y3=[y3,0,0]; y=Y1+Y2+Y3; L=-2:1:5; figure(1); subplot(211);stem(L,y,'*'); xlabel('L');ylabel('y');title('(1)'); X=x.';X=X'; r1=X*y(1);r2=X*y(2);r3=X*y(3);r4=X*y(4); r5=X*y(5);r6=X*y(6);r7=X*y(7);r8=X*y(8); R1=[0, ...