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📄 my_cocr_c.asv

📁 求解线性系统的Krylov方法的工具箱
💻 ASV
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function [x,iter,flg,res]=my_cocr_c(A,b,tol,maxit,M1,D,M2,x0)
% [x,iter,flg,res]=my_cocr(A,b,tol,maxit,M1,D,M2,x0)
% This code implements cocr algorithm with preconditioners M1 and M2, D if
% necessary
% flg=0 success; flg=1 failed to convergent whin maxit iterations;
% flg = 2 singular T; flg = 3 an isotropic  basis vector encountered.

% Developed by: Guanghui Cheng UESTC China
% Date        : 2008-08-23
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

% Check the dimension of A and the right-hand vector b
[m,n]=size(A);
if m~=n
    error('The coefficient matrix must be square!')
end
[m_b,n_b]=size(b);
if n_b~=1
    error('b must be a vector!')
end
nz=nnz(A);
if m~=m_b
    error('The right-hand vecotor must have the same length of A!')
end

% Check the input arguments and assign the default value
if nargin<2
    error('Not enough input arguments!');
end

if (nargin < 3) | isempty(tol)
   tol = 1e-6;
end
if (nargin < 4) | isempty(maxit)
   maxit = min(n,20);
end

% if 'b' is zero then the solution is zero
norm_b=norm(b);
if norm_b==0
    x=0;
    iter=0;
    return;
end

% Check the preconditioners
if nargin>=5 & ~isempty(M1)
    existM1=1;
    if ~isequal(size(M1),[m,n])
        error('The preconditioners M1 should match the size of A!')
    end
else
    existM1=0;
end
if nargin>=6 & ~isempty(D)
    existD=1;
    if ~isequal(size(D),[m,n])
        error('The preconditioners D should match the size of A!')
    end
else
    existD=0;
end
if nargin>=7 & ~isempty(M2)
    existM2=1;
    if ~isequal(size(M2),[m,n])
        error('The preconditioners M2 should match the size of A!')
    end
else
    existM2=0;
end

% Check the initial guess x0
if nargin==8 & ~isempty(x0)
    if ~isequal(size(x0),[m,1])
        error('The initial guess x0 must have the same length of A')
    end
else
    x0=zeros(m,1);
end

if nargin>8
    error('Too many input arguments!')
end

% set up for the COCR method
flg = 1;
x=x0;
v=b-A*x;
tol = tol*norm_b;
p = zeros(n,1);
beta = 0;
w = v;
if existM1
    w = M1 \ w;
end
if existD
    w = D \ w;
end  
if existM2
    w = M2 \ w; 
end
res(1) = 0;
u = A*w;
Ap = A*p;
for iter = 1:maxit
    p = w + beta*p;
    Ap = u + beta*Ap;
    MAp = Ap;
    if existM1
        MAp = M1 \ MAp;
    end
    if existD
        MAp = D \ MAp;
    end  
    if existM2
        MAp = M2 \ MAp; 
    end
    alf = (w.'*u) / (Ap.'*MAp);
    x = x + alf*p;
    v = v - alf*Ap;
    res(iter) = norm(v);
    if res(iter) < tol
        flg = 0;
        return;
    end
    w = v;
    if existM1
        w = M1 \ w;
    end
    if existD
        w = D \ w;
    end  
    if existM2
        w = M2 \ w; 
    end
    u = A*w;
    beta = -(u.'*MAp)/ (Ap.'*MAp);
end

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