📄 ldlrk1.m
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% ldlrk1.m %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% function [L,d,p]=ldlrk1(L,d,alp,u)% computes LDL^T factorization for LDL^T+alp*uu^T% if alp>=0 or if the new factorization is definite % (both signalled by p=[]);% otherwise, the original L,d and % a direction p of null or negative curvature are returned%% d contains diag(D) and is assumed positive% % does not work for dimension 0%function [L,d,p]=ldlrk1(L,d,alp,u);test=0; % only for testing the routineif test, disp('enter ldlrk1') A=L*diag(d)*L'+(alp*u)*u';end;p=[];if alp==0, return; end;n=size(u,1);neps=n*eps;% save old factorizationL0=L;d0=d;% updatefor k=find(u~=0)', del=d(k)+alp*u(k)^2; if alp<0 & del<=neps, % update not definite p=zeros(n,1);p(k)=1; p(1:k)=L(1:k,1:k)'\p(1:k); % restore original factorization L=L0;d=d0; if test, indef=(p'*(A*p))/(abs(p)'*(abs(A)*abs(p))) disp('leave ldlrk1 at 1') end; return; end; q=d(k)/del; d(k)=del; % in C, the following 3 lines would be done in a single loop ind=k+1:n; c=L(ind,k)*u(k); L(ind,k)=L(ind,k)*q+(alp*u(k)/del)*u(ind,1); u(ind,1)=u(ind,1)-c; alp=alp*q; if alp==0, break; end;end;if test, A1=L*diag(d)*L',A quot=norm(A1-A,1)/norm(A,1) disp('leave ldlrk1 at 2')end;
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