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📄 ex6_01.c

📁 [C语言入门经典(第4版)]整本书的源码!值得推荐!全部是最简单的源码!
💻 C
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/* Exercise 6.1 Convert an integer to words */
#include <stdio.h>
#include <string.h>

int main(void)
{
  char *unit_words[] = {"zero", "one","two","three","four","five","six","seven","eight","nine"};
  char *teen_words[] = {"ten", "eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"};
  char *ten_words[] = {"error", "error","twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety"};
  char hundred[] = " hundred";
  char and[] = " and ";
  char value_str[50] = "";
  int value = 0;                     /* Integer to be converted        */
  int digits[] = {0,0,0};            /* Stores digits of value entered */
  int i = 0;

  printf("Enter a positive integer less than 1000: ");
  scanf("%d",&value);
  if(value >= 1000)
    value = 999;
  else if(value < 1)
    value = 1;

  while(value > 0)
  {
    digits[i++] = value%10;
    value /= 10;
  }

  if(digits[2] > 0)
  {
    strcat(strcat(value_str,unit_words[digits[2]]), hundred);
    if(digits[1]>0 || digits[0]>0)
      strcat(value_str, and);
  }
  if(digits[1] > 0)
  {
    if(digits[1] == 1)
      strcat(value_str,teen_words[digits[0]]);
    else
    {
      strcat(value_str,ten_words[digits[1]]);
      if(digits[0] > 0)
        strcat(strcat(value_str, " "), unit_words[digits[0]]);
    }
  }
  else
    if(digits[0] > 0)
      strcat(value_str, unit_words[digits[0]]);
  printf("\n%s\n", value_str);
  return 0;
}

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