point2bin.c

cordic implementation in vhdl&c

////////////////////////////////////////////////////////////////////////////////
//                        Coypright (C) Aviral Mittal.
////////////////////////////////////////////////////////////////////////////////
//   All rights reserved. Reproducion in whole or in part is prohibited without 
//   written consent of copyright Owner.The professional use of this material 
//   is subject to the copy right owners approval in written. 
////////////////////////////////////////////////////////////////////////////////
//                   Comments welcome on [e-mail]
//                   Visit http://www.vlsiip.com for more free stuff
////////////////////////////////////////////////////////////////////////////////
// This program converts the fractional part of a number into binary bits
// The input given to this program will NOT have any decimal(point) in it
// Example: ./point2bin 45823
// Above is an example, where the user is trying to convert 0.45823 into binary
// ./point2bit 45823
//  0111010101001110
////////////////////////////////////////////////////////////////////////////////
#include <stdio.h>

double pvalues;
double inval = 0.0;
int tothepower = 2;
char inlen = 0;
char mystring[10] ;
char *pmystring ; //pointer to mystring
char error = 0;
char resbin[32]; //binary result
char i;//loop variable;
char binbits = 32;

long int  po(short int x,short int y);

int main(int argc, char* argv[]) {
//Initialization
  pmystring = &mystring[0];
  pvalues = 1/(double) tothepower;
//Initialization Ends

  if(argc == 2) {
    //calculate length of input string and copy it into my string
    while (*argv[1] != '\0') {
      //check if the input is essentialy numerical
      if(*argv[1] >= '0' && *argv[1] <= '9') {
        //printf("Input OK\n");
      } //if(*argv[1] >= '0' && *argv[1] <= '9')
      else {
        //printf("Input NOT OK\n");
        error = 1; //One or more input elemets are reported to be non-numeric
      }// else of if(*argv[1] >= '0' && *argv[1] <= '9')
      //check if the input is essentialy numerical Ends
      *pmystring = *argv[1];
      *argv[1]++;
      *pmystring++;
      inlen++;
    } //while (*argv[1] != '\0')
    *pmystring = '\0';
     pmystring = &mystring[0];
 
    //#printf("inlen = %d\n",inlen);
    //printf("mystring = %s\n",mystring);
////////////////////////////////////////////////////////////////////////////////
    //Convert the string into an integer/double but ONLY if error=0
////////////////////////////////////////////////////////////////////////////////
    if(error == 0) {

      //Convert Input String into a double
      for(i=0;i<inlen;i++){
        //#printf("Input = %d\n",mystring[i]-48); //Here
        inval = (((double) (mystring[i]-48)))/po(10,(i+1)) + inval;
      }// for(i=0;i<inlen;i++)
      printf("input number is evluated as %f\n",inval);
      //Convert Input String into a double Ends

      for(i=0;i<binbits;i++) {
       //#### printf("pvalues for this itration = %f\n",pvalues);
        if(inval >= pvalues) {
          inval = inval-pvalues;
          resbin[i] = '1';
        }
        else {
          resbin[i] = '0';
        }
        //printf("resbin[i] = %d\n",resbin[i]);
        tothepower = tothepower*2;
        pvalues = 1/(double) tothepower;
      } //for(i=0;i<binbits<i++)
        resbin[binbits] = '\0';
        printf("%s\n",resbin);
        //##printf("resbin = %s\n",resbin);
    }//if(error == 0)
    else {
       printf("Cannot convert Input, because Input format NOT numeric\n");
    }// else of if(error == 0)
////////////////////////////////////////////////////////////////////////////////
  }//if(argc == 2)
  else {
    printf("\n");
    printf("########################################################\n");
    printf("Error: Not correct Arguments\n");
    printf("This program converts the fractional part of any number into \n");
    printf("Binary suitable for Fixed Point Representation \n");
    printf("\n");
    printf("Example: To convert 0.76283 Into Binary \n");
    printf("Unix> point2bit 76283 \n");
    printf("1100001101001000\n");
    printf("\n");
    printf("Note that ONLY the digits after the decimal are given as input\n");
    printf("The INPUT format: ONLY the digits following a '.' can be given\n");
    printf("########################################################\n");
    printf("\n");

  } // else of if(argc == 2)
}//int main(int argc, char* argv[])


//Functions Declaration

long int  po(short int x,short int y)
{
  //to Calculate 10^4, po(10,4);
  int j;
  long int ret=1;
  for(j=0;j<y;j++) {
    ret = ret*x;
  }
  return(ret);
}

//Functions Declaration Ends