1.c

实现一个简单的电子钟的功能

#include<AT89x51.h>
 
void ms(unsigned int Delay)
{unsigned int a;
  for(;Delay>0;Delay--)
  {for(a=0;a<125;a++)
   {;}
  }
}

void dingshi1()
{
 TMOD=1;
 TH0=0x4C;
 TL0=0;
 TR0=1;
}

void dingshi2()
{
 TF0=0;
 TH0=0x4C;
 TL0=0;
}

void int0_srv() interrupt 0 using 1
{
 if(INT0=0)
 {
  if(P2_1==0) {i+=60;P1=48+i/60%60%10;P1=64+i/60%60%10;ms(200);}
  if(P2_2==0) {i+=3600;P1=i/3600%24/10;P1=16+i/3600%24/10;;ms(200);}
 }
}
void main(void)
{
  unsigned long k=0,year=2006,yue=10,day=16,i;
  unsigned int qiao=0,cha=0,a=0;
  dingshi1();
   P1=16;P1=32+15;P1=48;P1=64;P1=72+15;P1=96;P1=128+112;P1=0;
   P2=255;
   loop:   
   while(1)
   {
   i=b;
   if(TF0)
   {a++;
    if(a==20) {i++;a=0;}
   }
   b=i;
   if(P2_0==0) {qiao++;break;}
   if(i==k&&i!=0)P2_7=0;
   if(i==k+60)P2_7=1;
   if(i==86400) 
   {
    i=0;  
    day++;    
     if((yue==1||yue==3||yue==5||yue==7||yue==8||yue==10||yue==12)&&day==32)
       {
        day=1;
        yue++; 
       }
     if((yue==4||yue==6||yue==9||yue==11)&&day==31)
       {
        day=1;
        yue++; 
       }
     if(year%4==0&&yue==2&&day==30) 
      {
       day=1;
       yue++; 
      }
     else if(yue==2&&day==29)
        {
         day=1;
         yue++; 
        } 
    if(yue==13){yue=1; year++;}
   }
  }
   P1=48+k/60%60/10; P1=64+k/60%60%10;
   P1=k/3600%24/10; P1=16+k/3600%24%10;
   if(j==1&&P2_1==0)
   {k+=60;P1=48+k/60%60/10;P1=64+k/60%60%10;ms(100);}
   if(j==1&&P2_0==0)
   {k+=3600;P1=k/3600%24/10;P1=16+k/3600%24%10;ms(100);}
   ms(100);
   if(cha==0)
   {
    P1=112+i%60/10;
    P1=96+i%60/10; 
    P1=80+15;
    P1=64+i/60%60%10; 
    P1=48+i/60%60/10;
    P1=32+15;
    P1=16+i/3600%24%10;
    P1=128+i/3600%24/10;
   }
   if(cha==1)
   {
    P1=112+k%60/10;
    P1=96+k%60/10; 
    P1=80+15;
    P1=64+k/60%60%10; 
    P1=48+k/60%60/10;
    P1=32+15;
    P1=16+15;
    P1=128+15;
   }
   if(cha==2) 
   {    
    P1=112+day%10;
    P1=96+day/10%10; 
    P1=80+yue%10;
    P1=64+yue/10%10; 
    P1=48+year%10;
    P1=32+year/10%10;
    P1=16+year/100%10;
    P1=128+year/1000;   
   }
   if(cha==3)
   {
    P1=112+15;
    P1=96+15; 
    P1=80+15;
    P1=64+15; 
    P1=48+15;
    P1=32+15;
    P1=16+15;
    P1=128+week;   
   }   
  }
  while(qiao<8&&(qiao!=0))
  {
   if(P2_0==0) {qiao++;ms(300);}
   if(qiao==1)
   {if(P2_2==0) {b+=3600}
    P1=112+b%60/10;
    P1=96+b%60/10; 
    P1=80+15;
    P1=64+b/60%60%10; 
    P1=48+b/60%60/10;
    P1=32+15;
    P1=16+b/3600%24%10;
    P1=128+b/3600%24/10;
   }
   if(qiao==1)
   {
    P1=112+b%60/10;
    P1=96+b%60/10; 
    P1=80+15;
    P1=64+b/60%60%10; 
    P1=48+b/60%60/10;
    P1=32+15;
    P1=16+b/3600%24%10;
    P1=128+b/3600%24/10;
   }
  }
  j=0;
  goto loop;
}