📄 ei_1.m
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%ei_1(a): manually integrating int(e^(-t)/t, a,inf);
function eival=ei_1(a)
if a <=0
eival =0;
EXCEPTION= 'IN EI_1() A<0'
return;
end% not the case
if a >=1
eival = 0.22;
EXCEPTION= 'IN EI_1() A>1'
return;
end% value when a=1; our case is 0<a<1 since a=1/snr
eival=0;
%datestr(now)
stepp=(1-a)/1e5;
for ii=a:stepp:1
eival=eival+stepp*exp(-ii)/ii;
end
eival=eival+0.22;
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