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📄 dblfixpoint.c

📁 图形处理算法合集3:包括图形处理、帧缓存技术、渲染、矩阵运算、建模方法
💻 C
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#include <stdio.h>#include "fixpoint.h"static int verbose = 0;/* The dblfixpoint representation is signed magnitude, with  hi is 2n bits of integer (n <= 16)  lo is 2m bits of fraction (m <=16)number = hi + lo * 2^(-2m)*/int fp_dblnegative(dblfixpoint x) { return (x.neg); }dblfixpoint fp_dblnegate(dblfixpoint x){ x.neg = !x.neg;   return x; }dblfixpoint fp_dblmultiply(fixpoint x, fixpoint y){  dblfixpoint answer;  unsigned int a, b, c, d;  unsigned int xhi, xlo, yhi, ylo;  xhi = (x<0) ? -fp_integer(x) : fp_integer(x);  yhi = (y<0) ? -fp_integer(y) : fp_integer(y);  xlo = fp_fraction(x);  ylo = fp_fraction(y);  a = xhi * yhi;  b = xhi * ylo;  c = xlo * yhi;  d = xlo * ylo;  a += ((b & HIMASK) >> LOBITS);  a += ((c & HIMASK) >> LOBITS);  b = (b & LOMASK) + (c & LOMASK) + ((d & HIMASK) >> LOBITS);  a += ((b & HIMASK) >> LOBITS);  answer.hi = a;  answer.lo = ((b & LOMASK) << LOBITS) | (d & LOMASK);  answer.neg = 0;  if (((x<0) && (y>0)) || ((x>0) && (y<0))) answer = fp_dblnegate(answer);  return(answer);}int fp_dbllessthan(dblfixpoint x, dblfixpoint y){  int bothneg, xneg, yneg;  xneg = fp_dblnegative(x);  yneg = fp_dblnegative(y);  bothneg = xneg && yneg;  if (xneg && !yneg) return 1;  if (yneg && !xneg) return 0;  if (bothneg) {    x = fp_dblnegate(x);    y = fp_dblnegate(y);  }  if (x.hi < y.hi) return !bothneg;  if (y.hi < x.hi) return  bothneg;  if (x.lo < y.lo) return !bothneg;  return bothneg;}fixpoint fp_trunc(dblfixpoint a){  int hi = (a.hi << LOBITS);  int lo = (a.lo >> LOBITS);  if ((hi >> LOBITS) != a.hi) {	 printf("fp_trunc() Overflow converting hibits 0x%08x to 0x%08x fixpoint in (%d,%d) bits\n", a.hi, hi, HIBITS, LOBITS);  }  if (a.neg)	 return (-(hi + lo));  else	 return (hi + lo);}unsigned int add_with_carry(unsigned int a, unsigned int b,									 int carry_in, int *carry_out){  int ahi, bhi;  unsigned int answer;  *carry_out = 0;  ahi = (0x80000000 & a) ? 1 : 0;   /* Is high bit on? */  bhi = (0x80000000 & b) ? 1 : 0;  a &= 0x7fffffff;  b &= 0x7fffffff;  answer = a + b + carry_in;	  /* this can't overflow (I think) */  if (answer & 0x80000000) {	 if (ahi && bhi) *carry_out = 1;	/* Hi bit is on, leave it on */	 else if (ahi || bhi) {				/* Turn hi bit off, turn on carry */		*carry_out = 1;		answer &= 0x7fffffff;	 }  }  else {                    /* else (if answer high bit is off) */	 if (ahi && bhi) *carry_out = 1;	 else if (ahi || bhi) answer |= 0x80000000;  }  return(answer);}dblfixpoint fp_dbladd(dblfixpoint a, dblfixpoint b){  dblfixpoint answer;  if (verbose) printf("\nfpdbladd\n");  if ((a.neg && b.neg) || (!a.neg && !b.neg)) {	 int carry;	 answer.neg = a.neg;	 answer.lo = add_with_carry(a.lo, b.lo, 0, &carry);	 if (verbose && ((answer.lo >> 2*LOBITS) || carry))	        printf("  Lobits overflow (ok, put into hibits).\n");	 /*This puts lobit overflow into .hi, and removes from .lo */	 answer.hi = a.hi + b.hi + (answer.lo >> 2*LOBITS) + carry;	 answer.lo &= (LOMASK | (LOMASK << LOBITS));  }  else {	 if (a.neg) {		unsigned int tmp;		if (verbose) printf("\tCase: a.neg, b.pos, a<b, swapping\n");		a.neg = 0; b.neg =1;		tmp = a.hi; a.hi = b.hi; b.hi = tmp;		tmp = a.lo; a.lo = b.lo; b.lo = tmp;	 }	 if (a.hi < b.hi) {		if (a.lo <= b.lo) {		  if (verbose) printf("\tCase: a.pos, b.neg, a.hi<b.hi, a.lo<=b.lo \n");		  answer.neg = 1;		  answer.lo = b.lo - a.lo;		  answer.hi = b.hi - a.hi;		}		else {		  if (verbose) printf("\tCase: a.pos, b.neg, a.hi<b.hi, a.lo > b.lo \n");		  answer.neg = 1;		  answer.lo = (b.lo - a.lo) & (LOMASK | (LOMASK << LOBITS));		  answer.hi = b.hi - a.hi - 1;		}	 }	 else if ((a.hi == b.hi) && (a.lo < b.lo)) {		if (verbose) printf("\tCase: a.pos, b.neg, a.hi = b.hi, a.lo < b.lo \n");		  answer.neg = 1;		  answer.lo = b.lo - a.lo;		  answer.hi = 0;	 }	 else {		if (a.lo >= b.lo) {		  if (verbose) printf("\tCase: a.pos, b.neg, a.hi > b.hi, a.lo >= b.lo\n");		  answer.neg = 0;		  answer.lo = a.lo - b.lo;		  answer.hi = a.hi - b.hi;		}		else {		  if (verbose) printf("\tCase: a.pos, b.neg, a.hi > b.hi, a.lo < b.lo\n");		  answer.neg = 0;		  answer.lo = (a.lo - b.lo) & (LOMASK | (LOMASK << LOBITS));		  answer.hi = a.hi - b.hi - 1;		}	 }  }  return(answer);}

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