📄 kernel lda.m
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clear all;
close all;
ratio = 2;
class_num = 40;
sample_num = 10;
row_0 = 112;
line_0 = 92;
row = ceil(row_0/ratio);
line = ceil(line_0 / ratio);
row_line = min(row, line);
rowline = row * line;
load orl_2;
disp('orl Two-phase KFD algorithm now begin');
right_num = [];
rr_0 = [];
for count = 2:6
tic;
count
train_num = count;%每类样本训练数
train_total = train_num * class_num;%40类样本总的训练数M
test_num = sample_num - train_num;%每类样本测试数=样本数-训练数
test_total = test_num * class_num;%40类样本总的测试数
%%---step1:Perform KPCA in input space---%%
%%---求K---%%
l_m=(ones(train_total,train_total))/train_total;
orl_train = zeros(rowline, train_total);
for i = 1:class_num
for j = 1:train_num
kk = (i-1)*train_num + j;
orl_temp = double(orl(:,:,j,i));
for p = 1:row
for q = 1:line
site = (p-1)*line + q;
orl_train(site, kk) = orl_temp(p,q);
end
end
end
end
orl_test = zeros(rowline, test_total);
for i = 1:class_num
for j = 1:test_num
kk = (i-1)*test_num + j;
orl_temp = double(orl(:,:,j+train_num,i));
for p = 1:row
for q = 1:line
site = (p-1)*line + q;
orl_test(site, kk) = orl_temp(p,q);
end
end
end
end
K1=zeros(train_total,train_total);%利用orl_train求K~=k(Xi,Xj),Xi为训练样本中的特征向量
K2=zeros(test_total,test_total);%利用orl_test求K~=k(Xi,Xj),Xi为测试样本中的特征向量
for i=1:train_total
for j=i:train_total
%K1(i,j)=((orl_train(:,i))'*(orl_train(:,j))+1).^2;%选择多项式函数为kernel函数
K1(i,j)=(orl_train(:,i))'*(orl_train(:,j))+1;%选择线性函数为kernel函数
K1(j,i)=K1(i,j);
end
end
for i=1:test_total
for j=i:test_total
%K2(i,j)=((orl_test(:,i))'*(orl_test(:,j))+1).^2;
K2(i,j)=(orl_test(:,i))'*(orl_test(:,j))+1;
K2(j,i)=K2(i,j);
end
end
K=K1-l_m*K1-K1*l_m+l_m*K1*l_m;
K_test=K2-l_m*K2-K2*l_m+l_m*K2*l_m;
%%---求K的前m个非负特征值及其对应的特征向量,m为K的秩---%%
m=rank(K) - class_num;
[V_K, D_K] = eig(K);%求K的前m个大于0的最大本征值及其对应的标准正交本征向量
%V_K1 = orth(V_K);
dd = abs(eig(K));
[dd_value, dd_site] = sort(dd);
temp2 = m;
temp1 = train_total - temp2 + 1;
yy = [];
Dt = zeros(temp2);
jj = 0;
for i = train_total:-1:temp1
yy = [yy; V_K(:,dd_site(i))'];
jj = jj + 1;
Dt(jj,jj) = dd_value(i);
end
yy = orth(yy');
%yy = yy';
D_K1=diag(Dt);
%%利用等式(16)进行KPCA转换%%
y_temp=zeros(train_total,temp2);
for i=1:train_total
for j=1:temp2
y_temp(i,j)=yy(i,j)/sqrt(D_K1(j));
end
end
for i=1:train_total
y_train(:,i)=y_temp'*K(:,i);
y_test(:,i)=y_temp'*K_test(:,i);
end
%%---step 2:Perform LDA in KPCA-transformed space---%%
%%利用等式(17)求Sb%%
y_m_all = zeros(m,1);
y_m = zeros(m,class_num);
kk = 0;
for i = 1:class_num
for j = 1:sample_num
if train_mark(j) == 1
kk = kk + 1;
y_m_all = y_m_all + y_train(:,kk);
y_m(:,i) = y_m(:,i) + y_train(:,kk);
end
end
y_m(:,i) = y_m(:,i)/train_num;
end
y_m_all = y_m_all / train_total;
Sb1 = zeros(m,class_num);
Sb = zeros(m,m);
for i = 1:class_num
Sb1(:,i) = y_m(:,i) - y_m_all;
Sb = Sb + train_num*Sb1(:,i)*Sb1(:,i)';
end
Sb=Sb/train_total;
Sw1 = zeros(m,train_total);
Sw = zeros(m,m);
kk = 0;
for i = 1:class_num
for j = 1:sample_num
if train_mark(j) == 1
kk = kk + 1;
Sw1(:,kk) = y_train(:,kk) - y_m(:,i);
Sw = Sw + Sw1(:,kk)*Sw1(:,kk)';
end
end
end
Sw=Sw/train_total;
St1 = zeros(m,train_total);
St = zeros(m,m);
kk = 0;
for i = 1:class_num
for j = 1:sample_num
if train_mark(j) == 1
kk = kk + 1;
St1(:,kk) = y_train(:,kk) - y_m_all;
St = St + St1(:,kk)*St1(:,kk)';
end
end
end
St=St/train_total;
%clear y_m_all y_m;
%%计算St的前d个最大本征值及其对应的本征向量%%
ss = inv(Sw)*Sb;
% ss = St;
[V_ss, D_ss] = eig(ss);
dd = abs(eig(ss));
[dd_value, dd_site] = sort(dd);
temp2 = class_num - 1; %rank(ss)
temp1 = m - temp2 + 1;
G = [];
for i = m:-1:temp1
v_temp = V_ss(:,dd_site(i))';
G = [G; v_temp];
end
dd_bak = dd_value(temp1:m)';
toc;
%% -------- 4.calculate transform of test and train -------- %%
orl_train_new = G * y_train;
orl_test_new = G *y_test;
error = [];
for i = 1:class_num
for j = 1:test_num
%i,j
kk = (i-1)*test_num + j;
res_y = orl_test_new(:,kk);
dis = [];
for ii = 1:class_num
for jj = 1:train_num
res_x = orl_train_new(:,(ii-1)*train_num+jj);
res = (res_y - res_x).^2;
temp = sqrt(sum(res));
res = abs(res_y - res_x);
temp = sum(res);
dis = [dis; temp];
end
end
[value, site] = min(dis);
site_new = floor((site-1)/train_num) + 1;
if site_new ~= i
error = [error; i*test_num+j];
end
end
end
right_num = [right_num; (1.0-length(error)/(class_num*test_num))*100 ];
right_num'
end
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