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17.7.5 交集(具有长度限制的与操作)</div>
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当我们希望两个操作数能够匹配,并且操作数序列的结束时间必须相同的时候,我们可以使用<span style="color: #0000FF">intersect</span>二元操作符。 </p><div class="Element170">
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<div class="Element13"><div class="Element12" id="code00624"><pre class="Element12">sequence_expr ::= <span style="color: #008000">// 引用自附录A.2.10</span>
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| sequence_expr <strong><span style="color: #FF0000">intersect</span></strong> sequence_expr</pre></div></div>
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<strong>语法17-7 — 交集操作符语法(摘录自附录A)</strong></p><p class="Element10">
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<span style="color: #0000FF">intersect</span>操作的两个操作数都是序列。<span style="color: #0000FF">intersect</span>操作匹配的要求如下:
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<li class="Element601">两个操作数都必须匹配。</li>
<li class="Element601">操作数序列的两个匹配长度必须相同。</li>
</ul>有关序列长度的其它要求是<span style="color: #0000FF">and</span>操作与<span style="color: #0000FF">intersect</span>操作的基本差别。 </p>
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一个<span style="color: #0000FF">intersect</span>序列的计算尝试会产生多个匹配。这样的一个尝试的结果可以按如下方式计算。
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<li class="Element601">具有相同长度的第一个和第二个操作数的匹配是成对的。每一个这样的对都会产生一个复合序列的匹配,其长度和结束点等于操作数序列成对匹配的共享长度和结束点。</li>
<li class="Element601">如果没有找到这样的对,那么复合序列不会匹配。</li>
</ul>除了使用<span style="color: #0000FF">intersect</span>替代<span style="color: #0000FF">and</span>外,图17-7类似于图17-5。在这个例子中,与图17-5不同,只在时钟标记12处具有单个匹配。 </p><p class="Element10" style="text-align: center">
<img src="Figure_17_7.png" border="0" alt="" title=""><strong>图17-7 — 两个序列的交集</strong></p></div>
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