c02p106.txt

来自「Data Abstraction & Problem Solving with 」· 文本 代码 · 共 26 行

// Exercise 11

int getValue(int a, int b, int n);

int main()
{
   cout << getValue(1, 7, 7) << endl;
   return 0;
}  // end main

int getValue(int a, int b, int n)
{
   int returnValue;

   cout << "Enter: a = " << a << " b = " << b << endl;

   int c = (a + b)/2;
   if (c * c <= n)
      returnValue = c;
   else
      returnValue = getValue(a, c-1, n);

   cout << "Leave: a = " << a << " b = " << b << endl;
   return returnValue;
}  // end getValue