ac1334.pas
来自「Ural(Acm.timus.ru)题解 By Maigo大牛」· PAS 代码 · 共 23 行
PAS
23 行
program ural1334;
const
dx:array[1..8]of shortint=(-1,-1,-1,0,1,1,1,0);
dy:array[1..8]of shortint=(-1,0,1,1,1,0,-1,-1);
var
a:array[0..9,0..9]of byte;
i,x,y,d:byte;
c:char;
begin
fillchar(a,sizeof(a),2);
for i:=1 to 32 do begin
readln(c,y);
x:=ord(c)-96;
for d:=1 to 8 do
if a[x+dx[d],y+dy[d]]+i and 1=1 then begin
writeln(i);
halt;
end;
a[x,y]:=i and 1;
end;
writeln('Draw');
end.
⌨️ 快捷键说明
复制代码Ctrl + C
搜索代码Ctrl + F
全屏模式F11
增大字号Ctrl + =
减小字号Ctrl + -
显示快捷键?