ac1164.pas
来自「Ural(Acm.timus.ru)题解 By Maigo大牛」· PAS 代码 · 共 27 行
PAS
27 行
program ural1164;
var
count:array['A'..'Z']of byte;
n,m,p,i,j:byte;
c:char;
begin
readln(n,m,p);
for i:=1 to n do begin
for j:=1 to m do begin
read(c);
inc(count[c]);
end;
readln;
end;
for i:=1 to p do begin
repeat
read(c);
dec(count[c]);
until eoln;
readln;
end;
for c:='A' to 'Z' do
for i:=1 to count[c] do
write(c);
writeln;
end.
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