ac1025.pas
来自「Ural(Acm.timus.ru)题解 By Maigo大牛」· PAS 代码 · 共 25 行
PAS
25 行
program ural1025;
const
maxk=101;
var
p:array[1..maxk]of integer;
k,i,j:byte;
t:integer;
begin
readln(k);
for i:=1 to k do
read(p[i]);
for i:=1 to k-1 do
for j:=i+1 to k do
if p[i]>p[j] then begin
t:=p[i];p[i]:=p[j];p[j]:=t;
end;
k:=k div 2+1;t:=0;
for i:=1 to k do
inc(t,p[i] div 2+1);
writeln(t);
end.
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