📄 unc_n2_ackley.m
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function [fval]=unc_n2_Ackley(x)
%reference:
%note that you can get the formulation of unc_n2_Ackley from some
%aritcles,such as
%(1)
%algorithm:
%below code is edited according to
%(1)
%
%solution:
% where the bounds are -5<=x1,x2<=5;
% The global minimum is at x*=(0,0)
%and f(x*)=-0.0054618;
%there are about 100 global minima!
%Copyright:
% programmers:oiltowater.
% It comply with the GPL2.0
% Copyright 2006 oiltowater
x1=x(1,1);
x2=x(2,1);
fval=-20*exp(-0.2*(0.5*(x1.^2+x2.^2))^2)-exp(0.5*(cos(2*pi*x1)+cos(2*pi*x2)))+22.71282;
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