代码搜索结果

<mark>y</mark>=dsolve('D2<mark>y</mark>=cos(2*x)-<mark>y</mark>','D<mark>y</mark>(0)=0','<mark>y</mark>(0)=1') <mark>y</mark>=simple(<mark>y</mark>) <mark>y</mark>=dsolve('D2<mark>y</mark>-2D<mark>y</mark>-3*<mark>y</mark>=0') <mark>y</mark>=dsolve('D2<mark>y</mark>-2D<mark>y</mark>-3*<mark>y</mark>=0','<mark>y</mark>(0)=0','<mark>y</mark>(1)=1') <mark>y</mark>=simple(<mark>y</mark>) prett<mark>y< ...

y=[]; A=[71 27 34 37 18 33;20 18 17 13 12 28;7 9 0 7 6 5;4 3 0 4 2 0;1 3 1 0 2 5]; for a=0:1 for b=0:2 for c=0:3 for d=0:2 for e=0:4

y=linspace(.1,1,100); thr=0.28; ythard=wthresh(y,'h',thr); ytsoft=wthresh(y,'s',thr); subplot(2,2,1); plot(y); title('原始信号'); subplot(2,2,3); plot(ythard); title('硬阈值信号'); s

y=randn(1,1000); thr1=thselect(y,'rigrsure') thr2=thselect(y,'sqtwolog') thr3=thselect(y,'heursure') thr4=thselect(y,'minimaxi')

Y + * * + *

y( 0)=5.40000e+01 yy( 0)=5.68429e+01 y( 1)=1.45000e+02 yy( 1)=1.33629e+02 y( 2)=2.27000e+02 yy( 2)=2.44057e+02 y( 3)=3.59000e+02 yy( 3)=3.47943e+02 y( 4)=4.01000e+02 yy( 4)=3.93457e+02

y( 0)=0.00000e+00 y( 1)=1.86090e-02 y( 2)=3.25359e-02 y( 3)=4.20480e-02 y( 4)=4.73684e-02 y( 5)=4.86842e-02 y( 6)=4.61538e-02 y( 7)=3.99123e-02 y( 8)=3.00752e-02 y( 9)=1.67423e-02 y(10)=0.

y=0; n=100; for i=1:n y=y+1/(2*i-1); end y