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找到约 10,000 项符合 I 的代码

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modMethod = 144, 235, 652, 621, C frmNorm = 48, -6, 556, 380, , 22, 29, 623, 415, C modCall = 44, 58, 574, 391,

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Attribute VB_Name = "modMethod" Option Explicit '求正态分布的分位数 'Q:上侧概率 'x:分位数 Public Sub PNorm(Q, x) Dim p As Double, y As Double, z As Double Dim b0 As Double, b1 As Double, b2 As Double

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Type=Exe Reference=*\G{00020430-0000-0000-C000-000000000046}#2.0#0#C:\WINDOWS\System32\stdole2.tlb#OLE Automation Module=modMethod; 正态分布分位数M.bas Module=modCall; 正态分布分位数M1.bas Startup="Sub Main" C

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Attribute VB_Name = "modCall" Option Explicit '调用求分位数的过程 Sub main() Dim x As Double, dblI As Double For dblI = 0.05 To 0.45 Step 0.05 PNorm dblI, x Debug.Print "上侧概率="

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modMethod = 44, 58, 574, 391, C modCall = 66, 87, 596, 420,

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Attribute VB_Name = "modMethod" Option Explicit '计算正态分布函数 'x:正态偏离点 'F:下侧概率 Public Sub Norm(x, F) Dim y As Double, ER As Double, Q As Double Dim A Const a1 As Double = 0.0705230784

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Attribute VB_Name = "modCall" Option Explicit '调用计算正态分布函数的子程序 Sub Main() Dim x, F For x = 1 To 5 Norm x, F '调用计算正态分布函数的子程序 Debug.Print "正态偏离点 x =", x, "下侧概率 F =", F

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VERSION 5.00 Begin VB.Form frmNorm Appearance = 0 'Flat BackColor = &H80000005& Caption = "正态分布" ClientHeight = 2250 ClientLeft = 60 Cli

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modMethod = 89, 68, 597, 454, frmNorm = 48, -6, 556, 380, , 22, 29, 623, 415, C modCall = 44, 58, 574, 391,

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Type=Exe Reference=*\G{00020430-0000-0000-C000-000000000046}#2.0#0#C:\WINNT\System32\stdole2.tlb#OLE Automation Module=modMethod; 正态分布M.bas Form=正态分布F.frm Module=modCall; 正态分布M1.bas Startup="frmN