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找到约 10,000 项符合 H 的代码

main.cmd

/* * Copyright (C) 2003 Texas Instruments Incorporated * All Rights Reserved */ /* *---------Main.cmd--------- * */ MEMORY { L2SRAM : o = 00000000h l = 00030000h L2CACHE : o = 0

edma1.cmd

/* * Copyright (C) 2003 Texas Instruments Incorporated * All Rights Reserved */ /* *---------edma1.cmd--------- * */ MEMORY { L2SRAM : o = 00000000h l = 00030000h L2CACHE : o =

edma1.cmd

/* * Copyright (C) 2003 Texas Instruments Incorporated * All Rights Reserved */ /* *---------edma1.cmd--------- * */ MEMORY { L2SRAM : o = 00000000h l = 00030000h L2CACHE : o =

edma1.cmd

/* * Copyright (C) 2003 Texas Instruments Incorporated * All Rights Reserved */ /* *---------edma1.cmd--------- * */ MEMORY { L2SRAM : o = 00000000h l = 00030000h L2CACHE : o =

lnk.cmd

-c -heap 0x400 -stack 0x400 /* very large stack for DSP programs. */ -lrts6200.lib MEMORY { vecs: o = 00000000h l = 00000200h IRAM: o = 00000200h l= 00020000h

lnk.cmd

-w -c -heap 0x400 -stack 0x400 /* very large stack for DSP programs. */ -lrts6201.lib MEMORY { BOOT: o = 0 ,l = 400h vecs: o = 00000400h l = 00000200h IRAM:

reg410.inc

;------------------------------------------------------------------------------- ; Copyright 1995-1996 KEIL Software, Inc. ; 8xCL410 Processor Declarations ;----------------------------------------

15.map

Start Stop Length Name Class 00000H 00044H 00045H DATA 00050H 0009FH 00050H STACK1 000A0H 000BEH 0001FH CODE Pro

ascii码转换成十六进制数.txt

标号: ASCH 功能:ASCII码转换成十六进制数 入口条件:待转换的ASCII码(30<mark>H</mark>~39<mark>H</mark>或41<mark>H</mark>~46<mark>H</mark>)在A中。 出口信息:转换后的十六进制数(00<mark>H</mark>~0F<mark>H</mark>)仍在累加器A中。 影响资源:PSW、A 堆栈需求: 2字节 ASC<mark>H</mark>: CLR C SUBB A,#30<mark>H</mark> JNB ACC.4,AS<mark>H</mark>1 SUBB A,#7 AS<mark>H</mark>1: RET ...

ascii码转换成十六进制数.txt

标号: ASCH 功能:ASCII码转换成十六进制数 入口条件:待转换的ASCII码(30<mark>H</mark>~39<mark>H</mark>或41<mark>H</mark>~46<mark>H</mark>)在A中。 出口信息:转换后的十六进制数(00<mark>H</mark>~0F<mark>H</mark>)仍在累加器A中。 影响资源:PSW、A 堆栈需求: 2字节 ASC<mark>H</mark>: CLR C SUBB A,#30<mark>H</mark> JNB ACC.4,AS<mark>H</mark>1 SUBB A,#7 AS<mark>H</mark>1: RET ...