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G 的代码
891230_01.c
// g++ 1.36.1 bug 891230_01
// g++ gives typedefs which are nested within class declarations a scope
// which is local to the class declaration itself. This causes examples
// like the following to
900127_01.c
// g++ 1.36.1 bug 900127_01
// g++ often fails to detect (and issue errors for) ambiguous overload
// situations. In such cases, one of the possibilities is chosen
// (apparently arbitrarily). Error
900428_03.c
// g++ 1.37.1 bug 900428_03
// g++ fails to detect cases where a constructor for a derived class invokes
// (either explicitly or implicitly) a private constructor for a base class.
// cfront 2.0 pa
900208_03.c
// g++ 1.36.1 bug 900208_03
// The Cfront 2.0 reference manual (5.3.3) says "This type must be an
// object type; functions cannot be allocated this way...".
// g++ fails to detect (at compile time)
900325_01.c
// g++ 1.37.1 bug 900325_01
// g++ fails to generate errors for attempts to declare a formal argument to
// be of a void type.
// keywords: formal parameter, void type
typedef void __void;
typedef
900221_01.c
// g++ 1.36.1 bug 900221_01
// Ref: 3.2
//
// Section 3.2 of the C++ 2.0 Reference Manual says:
//
// "Names of formal arguments for a function are treated as if they
// were declared in the outermos
900519_06.c
// g++ 1.37.1 bug 900519_06
// g++ allows the type given in an invocation of operator new to be a
// reference type.
// Since pointers to reference types are illegal, the required return type
// fro
900321_02.c
// g++ 1.37.1 bug 900321_02
// The following program exits with a nonzero status because the constructor
// is not called 3 times as it should be. This program exits with a zero
// status when compi
900215_01.c
// g++ 1.36.1 bug 900215_01
// g++ allows the definition of a type conversion operator `operator void'
// for class types, but subsequently fails to generate calls (where needed)
// for such type con
900404_07.c
// g++ 1.37.1 bug 900404_07
// It is illegal to use a cast to attempt to convert an object type
// to a non-scalar type (e.g. an array type).
// g++ fails to properly flag as errors such illegal use