代码搜索结果

/* a.out.h Copyright 1997, 1998, 1999, 2001 Red Hat, Inc. This file is part of Cygwin. This software is a copyrighted work licensed under the terms of the Cygwin license. Please consult the fil

A=[-0.2,0.5,0,0,0;0,-0.5,1.6,0,0;0,0,-14.3,85.8,0; 0,0,0,-33.3,100;0,0,0,0,-10]; B=[0; 0; 0; 0; 30]; Q=diag([10,20,6,2,5]); R=1; C=[1,0,0,0,0]; D=0; [K,P]=lqr(A,B,Q,R); eig(A-B*K) [K2,P2]=lq

A =[ 0 1 1 0 1 0 1 0 1 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 1 0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1 1 0 0 0 1 1 1 0 0 1 0 1 0 0 1 0 0 0 1 1 1 1 0 1 0 0 1 1 1 1 1 0 1 0 0 0 1 1 1 1 1 0 1 1

A = [1, 3, 5, 7; 2, 4, 6, 8]; [L, A1, M] = svd(A) L*A1*M' norm(A-ans)

<mark>A</mark>* 算法求解最短路径2008年07月17日 星期四 下午 03:26这个问题太老土了，但是绝对经典，我现在就在研究启发式搜索算法，用<mark>A</mark>*算法来做这个题目比较好了，给你一个很详细的介绍吧！ 下面的是以前数据结构与算法的版主st<mark>a</mark>rfish提供的，你好好看看吧。不错的 <mark>A</mark>* 算法求解最短路径 ------------------------------------------ ...

>> a.b = struct('z', {}); a.b

/* A program to test */ int x[10]; int minloc(int a[],int low,int high) { int i;int x; int k; k=low; x=a[low]; i=low+1; while(i

/* * @(#)A.java 1.0 03/10/14 * * You can modify the template of this file in the * directory ..\JCreator\Templates\Template_1\Project_Name.java * * You can also create your own project tem

A=[-0.2,0.5,0,0,0;0,-0.5,1.6,0,0;0,0,-14.3,85.8,0; 0,0,0,-33.3,100;0,0,0,0,-10]; B=[0; 0; 0; 0; 30]; Q=diag([10,20,6,2,5]); R=1; C=[1,0,0,0,0]; D=0; [K,P]=lqr(A,B,Q,R); eig(A-B*K) [K2,P2]=lq

// A.cpp : Defines the class behaviors for the application. // #include "stdafx.h" #include "A.h" #include "ADlg.h" #ifdef _DEBUG #define new DEBUG_NEW #undef THIS_FILE static char THIS_FI