代码搜索结果

P=[0.1254 0.2315 0.3297; 0.2315 0.3297 0.4376; 0.3297 0.4376 0.5425; 0.4376 0.5425 0.6078; 0.5425 0.6078 0.7119]'; T=[0.4376 0.5425 0.6078 0.7119 0.8685]; P_test=[0.6078 0.7119 0

%构建训练样本中的输入向量p p1=[-0.0909 0.4825 0.9580 0.6643 0.0350 -0.6224; -0.1408 0.3944 0.9718 0.7183 0.0423 -0.6620; -0.2500 0.1250 0.9688 0.5000 0.0000 -0.0625; -0.2984 0.3037 -0.7801 0.0419 -0.3665 -0.8

P=[0.2452 0.1466 0.1314 0.2243 0.5523 0.6642 0.7015 0.6981 0.6821 0.6945 0.7549 0.8215 0.2415 0.3027 0; 0.2217 0.1581 0.1408 0.2304 0.5134 0.5312 0.6819 0.7125 0.7265 0.6847 0.7826 0.8325 0.2385

#include #include #include #include #include #include"chap9_Jacobi.h " #include"chap9_QR.h " void main() { //========================

CCTV-9

50 0000000000000000000000001111111111111100000000000000000000000000 0000000000000000000001111111111111111111000000000000000000000000 0000000000000000001111110000000000000111111111100000000000000000