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5-5-2.m

%初始化正向权值w和反向权值v w=rands(18,2)/2+0.5; v=rands(5,18)/2+0.5; %输入向量P和目标向量T P=[0 0;0.5 0.5;0 0.5;1 3;0.5 1;1 0.5]; T=[1 0 0 0 0;1 0 0 0 0;0 1 0 0 0;0 0 1 0 0;0 0 0 1 0;0 0 0 0 1]; T_out=T; %设定学习步数为1

chapter5_5.m

a=[-0.5572,-0.7814;0.7814,0];b=[1;0]; c=[1.9691,6.4493];d=[0]; x0=[1;0];t=0:0.1:20; initial(a,b,c,d,x0,t)

ex5_5.m

x=0:pi/100:2*pi; y1=0.2*exp(-0.5*x).*cos(4*pi*x); plot(x,y1) hold on y2=2*exp(-0.5*x).*cos(pi*x); plot(x,y2); hold off

vtb5_5.m

function vtb5_5(ma,m,ca,ka,k,rfin) %VTB5_5 Normalized amplitude of the primary mass for a % damped vibration absorber design. % VTB5_5(ma,m,ca,ka,k,rfin) plots the normalized amplitude % for a system

ex5-5.c

#include struct ydate { unsigned int year; unsigned char month, day; }; leapyear(struct ydate d) { unsigned char leapy=0; if((d.ye

ex5_5.m

x=0:pi/100:2*pi; y1=0.2*exp(-0.5*x).*cos(4*pi*x); plot(x,y1) hold on y2=2*exp(-0.5*x).*cos(pi*x); plot(x,y2); hold off

cp5_5.m

%%%%%%%%%%% Comprehensive Problem 5.5 %%%%%%%%%%% % Discrete-Time Control Problems using % % MATLAB and the Control System Toolbox % % by J.H. Chow, D.K. Frederick, & N.W. Chbat

reinf5_5.m

%%%%%%%%%%% Reinforcement Problem 5.5 %%%%%%%%%%% % Discrete-Time Control Problems using % % MATLAB and the Control System Toolbox % % by J.H. Chow, D.K. Frederick, & N.W. Chbat

ex5_5.m

%%%%%%%%%%%%%%%%%% Example 5.5 %%%%%%%%%%%%%%%%%% % Discrete-Time Control Problems using % % MATLAB and the Control System Toolbox % % by J.H. Chow, D.K. Frederick, & N.W. Chbat