代码搜索：4
找到约 10,000 项符合「4」的源代码
代码结果 10,000
www.eeworm.com/read/203230/15363805
m chap4_4.m
%Define N+1 triangle membership function
clear all;
close all;
N=2;
x=0:0.1:100;
for i=1:N+1
f(i)=100/N*(i-1);
end
u=trimf(x,[f(1),f(1),f(2)]);
figure(1);
plot(x,u);
for j=2:N
www.eeworm.com/read/202322/15386679
txt test4_4a.txt
#include
#include
#include
typedef struct TAG_datastruct{
char* string;
int checksum;
}datastruct;
datastruct* gerinput(void);
void printmessage(datastr
www.eeworm.com/read/202322/15386680
txt test4_4.txt
#include
#include
#include
typedef struct TAG_datastruct{
char* string;
int checksum;
}datastruct;
datastruct* getinput(void);
void printmessage(datas
www.eeworm.com/read/202322/15386806
txt test4_4a.txt
#include
#include
#include
typedef struct TAG_datastruct{
char* string;
int checksum;
}datastruct;
datastruct* gerinput(void);
void printmessage(datastr
www.eeworm.com/read/202322/15386807
txt test4_4.txt
#include
#include
#include
typedef struct TAG_datastruct{
char* string;
int checksum;
}datastruct;
datastruct* getinput(void);
void printmessage(datas
www.eeworm.com/read/202273/15387209
ppt ch4-4.ppt
www.eeworm.com/read/201868/15394139
m example4_4.m
%分别定义两段时间Time1和Time2，对应信号的不同频率时段
Time1=0:0.05:4;
Time2=4.05:0.024:6;
Time=[Time1 Time2];
%得到待预测的目标信号
T=[cos(Time1*4*pi) cos(Time2*8*pi)];
T=con2seq(T);
%绘出目标信号的曲线，并指定给输入
figure;
plot(Time,cat
www.eeworm.com/read/201037/15418070
cpp exam4-4.cpp
#include
#include
#include
#include "Exam4-2String.h" //包含顺序串类
void main(void)
{
// String s = ("cddcdc"), t = ("abcde"); //测试例子1
String s = ("aaaa