代码搜索：4
找到约 10,000 项符合「4」的源代码
代码结果 10,000
www.eeworm.com/read/193537/8218604
m example4_4.m
%分别定义两段时间Time1和Time2，对应信号的不同频率时段
Time1=0:0.05:4;
Time2=4.05:0.024:6;
Time=[Time1 Time2];
%得到待预测的目标信号
T=[cos(Time1*4*pi) cos(Time2*8*pi)];
T=con2seq(T);
%绘出目标信号的曲线，并指定给输入
figure;
plot(Time,cat
www.eeworm.com/read/394400/8226480
jpg pic_4_4.jpg
www.eeworm.com/read/193048/8255676
m ex4_4.m
% ex4_4
% 二阶环节的奈魁斯特图
figure('pos',[30 100 260 260],'color','w');
axes('pos',[0.15 0.2 0.7 0.7]);
wn=1;
w=[0,logspace(-2,5,200)];
for zeta=[0.5 1 5]
G=tf(1,[wn^-2 2*zeta/wn 1]);
nyq
www.eeworm.com/read/294008/8258053
m example4_4.m
%将两幅灰度图像合并成一个具有两帧的图像阵列，然后再调用imshow函数来显示第
%一帧图像。
A1=imread('rice.tif');
A2=imread('testpat1.tif');
A=cat(3,A1,A2); %用cat函数实现矩阵的合并
imshow(A(:,:,1)) %1代表第一帧
www.eeworm.com/read/293928/8262396
c 4_1_4.c
/* ======================================== */
/* 程式实例: 4_1_4.c */
/* 再论环状链结串列的插入和删除 */
/* ============================
www.eeworm.com/read/293882/8266028
cpp algo4-4.cpp
// algo4-4.cpp 根据algo4-3.cpp产生的文件,索引查询图书
#include"c1.h"
typedef int ElemType;
#include"c2-5.h"
#include"bo2-6.cpp"
#include"c4-2.h"
#include"bo4-2.cpp"
#define MaxBookNum 10 // 假设只对10
www.eeworm.com/read/192910/8266668
gif t4_4.gif
www.eeworm.com/read/293882/8266973
c algo4-4.c
www.eeworm.com/read/393745/8267349
c sample4_4.c
#include
#include /* Needed if linking in external compiler; harmless otherwise */
#include
#include "sample4_4.h"
static int panelHandle;
char pass1[15],pass2[15];