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sol_4_4.txt
726
A B A E F E C B A E C D F B A F A
chap4_4.m
%Adaptive PID control based on RBF Identification
clear all;
close all;
xite=0.25;
alfa=0.05;
belte=0.01;
x=[0,0,0]';
ci=30*ones(3,6);
bi=40*ones(6,1);
w=10*ones(6,1);
h=[0,0,0,0,0,0]
algo4-4.c
/* algo4-4.c 生成书名关键词索引文件bookidx.txt，算法4.9～4.14 */
/* 为运行algo4-5.c做准备 */
#include"c1.h"
typedef int ElemType;
#include"c2-5.h"
#include"bo2-6.c"
#include"c4-2.h"
#include"bo4-2.c"
#d
例4-4.c
/* 直到型循环结构示例 */
#include
void main()
{
char ch;
char buf[256];
char *p;
printf("Input a string.\n"); // 读取字符串
scanf("%s", buf);
p = buf;
do
{
ch = *p; //
ch4_4.cpp
//*********************
//** ch4_4.cpp **
//*********************
#include
#include
#include
void main()
{
double s=0,x=1; //初始值
long k=1;
4-4-2.m
function c=bsb(x,beta,multi)
% function c=bsb(x,beta)
%
% This m-file duplicates the Brain State in a Box Experiment.
% x - input vector
% beta - feedback factor
% c - numb
4-1-4.m
P=[0.4413 0.4707 0.6953 0.8133 0.4379 0.4677 0.6981 0.8002 0.4517 0.4725 0.7006 0.8201;
0.4379 0.4677 0.6981 0.8002 0.4517 0.4725 0.7006 0.8201 0.4557 0.4790 0.7019 0.8211;
0.4517 0.4725 0.7006 0.82
exp4_4.m
clc
clear
close
%开环传递函数描述
numo=20;
deno=[1 8 36 40 0];
%求闭环传递函数
[numc,denc]=cloop(numo,deno,-1);
%绘制闭环系统的脉冲激励响应曲线
t=1:0.1:10;
[y,x]=impulse(numc,denc,t);
plot(t,y)
title('the impulse respo