For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 3
For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piec...
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查看全部352个资源 »it is a simulation about ML synchronization algorithm in OFDM systems,you can slao see a function pi
it is a simulation about ML synchronization algorithm in OFDM systems,you can slao see a function picture in its output,that s useful for a beginner...
Euler函数: m = p1^r1 * p2^r2 * …… * pn^rn ai >= 1 , 1 <= i <= n Euler函数： 定义：phi(m) 表示小于等
Euler函数: m = p1^r1 * p2^r2 * …… * pn^rn ai >= 1 , 1 <= i <= n Euler函数： 定义：phi(m) 表示小于等于m并且与m互质的正整数的个数。 phi(m) = p1^(r1-1)*(p1-1) * p...
计算全息close all clc clear A=zeros(64) A(15:20,20:40)=1 A(15:50,20:25)=1 A(45:50,20:40)=1 A(30:34,
计算全息close all clc clear A=zeros(64) A(15:20,20:40)=1 A(15:50,20:25)=1 A(45:50,20:40)=1 A(30:34,20:35)=1 ％ ppp=exp(rand(64)*pi*2*i) A=A.*ppp ％...
// 入口参数： // l: l = 0, 傅立叶变换 l = 1, 逆傅立叶变换 // il: il = 0,不计算傅立叶变换或逆变换模和幅角；il = 1,计算模和幅角 // n: 输入的
// 入口参数： // l: l = 0, 傅立叶变换 l = 1, 逆傅立叶变换 // il: il = 0,不计算傅立叶变换或逆变换模和幅角；il = 1,计算模和幅角 // n: 输入的点数，为偶数，一般为32，64，128，...,1024等 // k: 满足n=2^k(k>...
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