壓縮演算法-基本的資料壓縮演算法-Run-length編碼的解壓縮程式~對應list1-3
标签： Run-length list 算法 程式
上传时间： 2016-08-15
上传用户：jeffery
資料壓縮技術與應用-變動長度編碼壓縮及解壓縮(Run length Encoding) 整數採用固定長度一個位元組表示法 對於只出現一次的位元組S亦用iS取代
上传时间： 2016-08-15
上传用户：GavinNeko
資料壓縮技術與應用-變動長度編碼壓縮(Run length Encoding)~ 整數採用固定長度一個位元組表示法~ 對於只出現一次的位元組S亦用iS取代~
上传时间： 2016-08-15
上传用户：asdfasdfd
Construct the short length of QC LDPC codes without girth 4 and girth 6
标签： girth Construct without length
上传时间： 2016-11-01
上传用户：ljt101007
Circular Convolution of two equal-length vectors. Highlights that circular convolution in the time domain is the effectively the same as element-by-element multiplication in the frequency domain.
标签： equal-length Convolution convolution Highlights
上传时间： 2014-01-22
上传用户：aig85
Instead of finding the longest common subsequence, let us try to determine the length of the LCS. Then tracking back to find the LCS. Consider a1a2…am and b1b2…bn. Case 1: am=bn. The LCS must contain am, we have to find the LCS of a1a2…am-1 and b1b2…bn-1. Case 2: am≠bn. Wehave to find the LCS of a1a2…am-1 and b1b2…bn, and a1a2…am and b b b b1b2…bn-1 Let A = a1 a2 … am and B = b1 b2 … bn Let Li j denote the length of the longest i,g g common subsequence of a1 a2 … ai and b1 b2 … bj. Li,j = Li-1,j-1 + 1 if ai=bj max{ L L } a≠b i-1,j, i,j-1 if ai≠j L0,0 = L0,j = Li,0 = 0 for 1≤i≤m, 1≤j≤n.
标签： the subsequence determine Instead
上传时间： 2013-12-17
上传用户：evil
This is the code about run length encoding
标签： encoding length about This
上传时间： 2017-03-14
上传用户：笨小孩
vba cad how to draw line and put its length
上传时间： 2017-04-06
上传用户：zaizaibang
Convolutional binary rate 1/3 nonsystematic code Dfree=16 K=7 (trellis length = 8) Connection vectors (from K. J. Larsen):
标签： Convolutional nonsystematic Connection trellis
上传时间： 2014-01-22
上传用户：181992417
Run length Encoding code in matlab
标签： Encoding length matlab code
上传时间： 2013-12-24
上传用户：liuchee
