current capacity 源代码

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源码文件

% MATLAB script for Illustrative Problem 2, Chapter 8. echo on pn0_db=[-20:0.1:30]; pn0=10.^(pn0_db./10); capacity=3000.*log2(1+pn…

源码文件

//: C18:StrSize.cpp // From Thinking in C++, 2nd Edition // at http://www.BruceEckel.com // (c) Bruce Eckel 1999 // Copyright …

源码文件

//: C01:StrSize.cpp // From Thinking in C++, 2nd Edition // Available at http://www.BruceEckel.com // (c) Bruce Eckel 2000 // …

源码文件

% MATLAB script for Illustrative Problem 8.2. clear echo on pn0_db=[-20:0.1:30]; pn0=10.^(pn0_db./10); capacity=3000.*log2(1+…

源码文件

import java.util.*; class vector { public static void main(String args[]) { Vector vector = new Vector(…

源码文件

//: C01:StrSize.cpp // From Thinking in C++, 2nd Edition // Available at http://www.BruceEckel.com // (c) Bruce Eckel 2000 // …

源码文件

function capacity %输出2-2系统的各态历经和截止容量 SNR=0:1:10;%SNR is signal-to-noise ratio in dBs subplot(2,1,1); output=capacity(2,1,0.5,1…

源码文件

//: C18:StrSize.cpp // From Thinking in C++, 2nd Edition // at http://www.BruceEckel.com // (c) Bruce Eckel 1999 // Copyright …

源码文件

% MATLAB script for Illustrative Problem 8.2. echo on pn0_db=[-20:0.1:30]; pn0=10.^(pn0_db./10); capacity=3000.*log2(1+pn0/300…

源码文件

% MATLAB script for Illustrative Problem 8.2. clear echo on pn0_db=[-20:0.1:30]; pn0=10.^(pn0_db./10); capacity=3000.*log2(1+…