北京大学ACM比赛题目 In 1742, Christian Goldbach, a German amateur mathematician, sent a letter to Leonhard Euler in which he made the following conjecture: Every even number greater than 4 can be written as the sum of two odd prime numbers. For example: 8 = 3 + 5. Both 3 and 5 are odd prime numbers. 20 = 3 + 17 = 7 + 13. 42 = 5 + 37 = 11 + 31 = 13 + 29 = 19 + 23. Today it is still unproven whether the conjecture is right. (Oh wait, I have the proof of course, but it is too long to write it on the margin of this page.) Anyway, your task is now to verify Goldbach s conjecture for all even numbers less than a million.
标签： mathematician Christian Goldbach Leonhard
上传时间： 2016-04-22
上传用户：wangchong
北京大学ACM比赛题目 Consider an infinite full binary search tree (see the figure below), the numbers in the nodes are 1, 2, 3, .... In a subtree whose root node is X, we can get the minimum number in this subtree by repeating going down the left node until the last level, and we can also find the maximum number by going down the right node. Now you are given some queries as "What are the minimum and maximum numbers in the subtree whose root node is X?" Please try to find answers for there queries.
标签： the Consider infinite numbers
上传时间： 2013-12-16
上传用户：日光微澜
北京大学ACM比赛题目 Write a program to read four lines of upper case (i.e., all CAPITAL LETTERS) text input (no more than 72 characters per line) from the input file and print a vertical histogram that shows how many times each letter (but not blanks, digits, or punctuation) appears in the all-upper-case input. Format your output exactly as shown.
标签： CAPITAL LETTERS program Write
上传时间： 2014-01-17
上传用户：410805624
用蛮力法解决的Acm icpc试题（求矩阵每一列列和的最小值）。
上传时间： 2016-04-22
上传用户：bruce
北大ACM在线做题网站的部分题目答案。代码为c++原码。
上传时间： 2013-12-27
上传用户：z1191176801
北大acm平台正版源代码acm2749
上传时间： 2016-04-29
上传用户：yzy6007
ACM题解 历年试题，经典题目，还有算法 前人经验等
上传时间： 2014-01-19
上传用户：invtnewer
这个一道ACM竞赛中的复杂模拟程序。按照国际象棋的规则，程序从check_in中读入双方落子的步骤 通过程序模拟该盘棋过程，并最后判断输赢。将结果仿真check_out中。
上传时间： 2016-05-02
上传用户：hakim
stl跟 acm的关系， 相当的好啊。。啊
上传时间： 2016-05-05
上传用户：sdq_123
Interface for Microsoft Audio Compression Manager. - Delphi Source The ACM uses existing driver interface hooks to override the default mapping algorithm for waveform audio devices. This allows the ACM to intercept device-open calls. After a call has been intercepted, the ACM can perform a variety of tasks to process the audio data, such as inserting an external compressor or decompressor into the sequence.
标签： Compression Interface Microsoft existing
上传时间： 2013-12-13
上传用户：541657925
