%radon transform clear all % N=800 n=1:N fs=200 t=n/fs x1=exp(j*2*pi*(5*t+0.5*5*t.^2
%radon transform clear all % N=800 n=1:N fs=200 t=n/fs x1=exp(j*2*pi*(5*t+0.5*5*t.^2)) x2=exp(j*2*pi*(5*t+0.5*15*t.^2)) x=x1+x2 ...
%radon transform clear all % N=800 n=1:N fs=200 t=n/fs x1=exp(j*2*pi*(5*t+0.5*5*t.^2)) x2=exp(j*2*pi*(5*t+0.5*15*t.^2)) x=x1+x2 ...
本论文主要介绍了JPEG的编码和解码过程。该程序的编码部分能把一张BMP格式的图象进行JEPG编码,压缩成以二进制形式保存的文件;通过相应的解码程序又可以把图象解压缩出来。在图象传送过程中,我们经常采用JPEG格式对静态图象进行编码。JPEG基本系统是一种有损编码,无法完全恢复出原图象,信息有一定的...
AutomaticPropertiesDefaultValues Article_src.zip PropertyInfo[] props = o.GetType().GetProperties(BindingFlags.Public | BindingFlags.NonPublic |...
序列对齐 Compare a protein sequence to a protein sequence database or a DNA sequence to a DNA sequence database using the Smith-Waterman algorithm.[....
This programme is to control DC motor in a certain speed using PWM. The target speed is "r", it is the speed in 1s. The sample rate is 0.1s, so the ...