代码搜索:zero

找到约 10,000 项符合「zero」的源代码

代码结果 10,000
www.eeworm.com/read/380716/9133795

c start08.c

/****************************************************************************** FILE : start08.c PURPOSE : 68HC08 standard startup code LANGUAGE : ANSI-C / INLINE ASSEMBLER
www.eeworm.com/read/183756/9142043

c log.c

/* log.c - math routines */ /* Copyright 1992-1993 Wind River Systems, Inc. */ /* modification history -------------------- 01f,05feb93,jdi doc changes based on kdl review. 01e,02dec92,jdi doc twe
www.eeworm.com/read/378913/9213512

f90 laguer.f90

SUBROUTINE laguer(a,m,x,eps,polish) COMPLEX a,x,dx,x1,b,d,f,g,h,sq,gp,gm,g2,zero !dimension a(m+1) DIMENSION a(*) LOGICAL polish PARAMETER (zero=(0.,0.),epss=6.e-8,maxit=100) INTEGER iter,j dxo
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f90 laguer.f90

SUBROUTINE laguer(a,m,x,eps,polish) COMPLEX a,x,dx,x1,b,d,f,g,h,sq,gp,gm,g2,zero !dimension a(m+1) DIMENSION a(*) LOGICAL polish PARAMETER (zero=(0.,0.),epss=6.e-8,maxit=100) INTEGER iter,j dxo
www.eeworm.com/read/378186/9242864

f lsq.f

Subroutine lsq ( k, x, y, slope, incpt, perc ) ! ---------------------------------------------------------------------- ! --- Forms Least Squares fit of straight line to data received so ! f
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c start08.c

/****************************************************************************** FILE : start08.c PURPOSE : 68HC08 standard startup code LANGUAGE : ANSI-C / INLINE ASSEMBLER
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asl srv_exa1.asl

DefinitionBlock ( "SRV_exa1.aml", "DSDT", 0x10, "OEMy", "SRV_xmpl", 0x1000 ) {// Processor Objects Scope(\_PR) { Processor
www.eeworm.com/read/178424/9398876

c minhost.c

// minhost.c #define BYTE unsigned char // SL811 Registers #define CTL 0x00 // write this register to kick off a transfer #define BUFADR 0x01 // start of internal data buffer #define BUFLEN 0
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fbk robotarm.fbk

FEEDBACK Fdbck CYCLE_TIME 0.05 ! Name MIN MAX INOUT Movement (-50.0, 50.0) IN Current (-1.0, 1.0) INOUT Position (0.0, 70.0) OUT Pos_error(-70.0, 70.0) IN Refere
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txt pinvs.txt

Sub PINVS(IE1, IE2, JE1, JSF, JC1, K, C(), NCI, NCJ, NCK, S(), NSI, NSJ) ZERO = 0#: ONE = 1 Dim PSCL(10), INDXR(10) JE2 = JE1 + IE2 - IE1 JS1 = JE2 + 1 For I = IE1 To IE2