代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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c 16进制10进制.c

自己写一个转换函数不就行了? //返回16进制字符串s对应的整数值,遇到任何一个非法字符都返回-1。 int HexToDec(char *s) { char *p = s; //空串返回0。 if(*p == '\0') return 0; //忽略开头的'0'字符 while(*p == '0') p++; int dec = 0;
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c 杨辉三角形.c

#include int c(x,y); main() { int i,j,n=13; printf("N="); while(n>12) scanf("%d",&n); for(i=0;i
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c 桶排序.c

#include void comp(int k[],int m,int l) { int i=10,j=0,z=1,y=1,x,w,b[500][10]; for(w=0;w
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c 1.1.c

#include main( ) { int p1,p2; while((p1=fork( ))== -1); /*创建子进程p1*/ if (p1==0) putchar('b'); else { while((p2=fork( ))== -1); /*创建子进程p2*/ if(p2==0) putchar('c')
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c 513.c

/*求100以内的所有素数*/ #include "math.h" main() {int n, div ,flag , r; n=2; while (n
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cpp qcksrt.cpp

void qcksrt(int n, double arr[]) { int m = 7; int nstack = 50; int fm = 7875; int fa = 211; int fc = 1663; double a,fmi = 0.00012698413; int istack[51]; int jstack = 0; int i,j,
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cpp sort2.cpp

void sort2(int n, double ra[], double rb[]) { int l,ir,i,j; double rra,rrb; l = n / 2 + 1; ir = n; do { if (l > 1) { l = l - 1; rra = ra[l];
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cpp indexx.cpp

void indexx(int n, double arrin[], int indx[]) { int i,j,l,ir,indxt; double q; for (j = 1; j
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cpp sort.cpp

void sort(int n, double ra[]) { int i,j,l,ir; double rra; l = int(n / 2) + 1; ir = n; do { if (l > 1) { l = l - 1; rra = ra[l]; }
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java clerk.java

import java.util.List; import java.util.Collections; import java.util.LinkedList; public class Clerk implements Runnable { Bank theBank; // The in-tray holding transactions: private List