代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
www.eeworm.com/read/304690/13789195

txt sin.txt

double sin(double d) { int signal=1; if(d=Dpi)d=d-Dpi; double r,t; //变量的初始值为0 int i=1,j; while(i
www.eeworm.com/read/304676/13789335

cpp mao.cpp

//程序名: yufashini.cpp //作者:小万(wbaobao) //邮箱:wbaobao#zj.com //QQ:421404493 //创建日期:2004.10 //程序功能:PL/0语言语法分析程序,检测pl/0源程序的语法是否正确 //程序不足之处:语言中对分程序的定义中没有包含常量的定义说明。错误处理能力不是很强。 /*各个符号和产生式说明 对应的函数    
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m a_sub.m

function a=a_sub(a1,a2) % % A=A_SUB(A1,A2) % Subtract two angles so that the result % always remains between +/- pi % % simple function to get angle subtraction consistent a=a1-a2; %
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m a_add.m

function a=a_add(a1,a2) % % A=A_ADD(A1,A2) % Add two angles so that the result % always remains between +/- pi % a=a1+a2; % get to within 2pi of the right answer a=a - (2.0*pi*fix(a/(2.0*
www.eeworm.com/read/304670/13789682

m a_sub.m

function a=a_sub(a1,a2) % % A=A_SUB(A1,A2) % Subtract two angles so that the result % always remains between +/- pi % % simple function to get angle subtraction consistent a=a1-a2; %
www.eeworm.com/read/304670/13789696

m a_add.m

function a=a_add(a1,a2) % % A=A_ADD(A1,A2) % Add two angles so that the result % always remains between +/- pi % a=a1+a2; % get to within 2pi of the right answer a=a - (2.0*pi*fix(a/(2.0*
www.eeworm.com/read/304589/13790946

c main.c

#define uchar unsigned char //定义一下方便使用 #define uint unsigned int #define ulong unsigned long #include //包括一个52标准内核的头文件 char code dx516[3] _at_ 0x003b;//这是为了仿真设置的 sbit P10=P1^
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c main.c

#define uchar unsigned char //定义一下方便使用 #define uint unsigned int #define ulong unsigned long #include //包括一个52标准内核的头文件 sbit P10 = P1^0; //头文件中没有定义的IO就要自己来定义了 sbit P11 = P1^1; sb
www.eeworm.com/read/304501/13792075

m m5.m

a3=[0,0,1,0,1];%初值 b3=zeros(1,31); u3=zeros(1,31); b3(1,1)=a3(1); for i=2:31 c31=a3(1); c32=a3(2); c33=a3(4); c34=a3(5); for j=2:5 a3(j-1)=a3(j);
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m m6.m

%6阶m序列 1+x+x^6% a=zeros(63,7) b=zeros(7,1) c=zeros(1,63) b=[0 0 0 0 0 1 0] a(1,6)=1 for i=2:63, temp=b(1,7); b(1,7)=b(1,6); b(1,6)=b(1,5); b(1,5)=b(1,4); b(1,4)=b(1,3);