代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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c 2_8a.c

/* ======================================== */ /* 程式实例: 2_8a.c */ /* 输入字串且将之印出 */ /* ======================================== */ #include
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cpp dct-ii.cpp

#include "conio.h" #include "stdio.h" #include "math.h" #include "stdlib.h" #include "sys/timeb.h" #define PI 3.14159265359 #define N 8 /* N 为2的幂 */ double F[2*N+1],C[2*N+1],y[2*N+1];
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cpp dct-iv.cpp

#include "conio.h" #include "stdio.h" #include "math.h" #include "stdlib.h" #include "sys/timeb.h" #define PI 3.14159265359 #define N 16 /* N 为2的幂 */ double F[2*N+1],C[2*N+1]
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cpp dct-iii.cpp

#include "conio.h" #include "stdio.h" #include "math.h" #include "stdlib.h" #include "sys/timeb.h" #define PI 3.14159265359 #define N 16 /* N 为2的幂 */ double F[2*N+1],C[2*N+1],y[2*N+1];
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c 1_pro.c

#include #include #include #include char xx[50][80] ; int maxline = 0 ;/* 文章的总行数 */ int ReadDat(void) ; void WriteDat(void) ; void StrOL(void)
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m gaijinnewton.m

syms f x; f=input('请输入f(x)='); df=diff(f); x0=input('请输入迭代初值x0='); e1=input('请输入奇异判断e1='); e2=input('请输入根的误差限e2='); N=input('请输入迭代次数限N='); k=1; while (k
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awk quiz.awk

# quiz - present a quiz # usage: awk quiz topicfile question-subj answer-subj # AKW p118 BEGIN { FS = ":" if (ARGC != 4) error("usage: awk quiz topicfile question answer")
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m one1.m

%n取值从小到大 n1=1; sum1=0; while(1) sum1=sum1+n1^(-2); %实现相加累计过程 if(n1>=10000) break; %控制n取值范围为1-10000 end n1=n1+1; %实现n从小到大取值 end fprintf('sum1=%e\n',su
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c 2440lib.c

//=================================================================== // File Name : 2440lib.c // Function : S3C2440 PLL,Uart, LED, Port Init // Date : March 20, 2002 // Version : 0.0 //
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lst 计算器.lst

C51 COMPILER V6.23a _芲闫_ 03/30/2007 21:30:12 PAGE 1 C51 COMPILER V6.23a, COMPILATION OF MODULE _芲闫_ OBJECT MODULE PLACED IN 计算器