代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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pas heapsort.pas

{ Просеивание } for i:= (N div 2)downto 1 do begin j:= i; while j
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pas insertionsort.pas

procedure InsertionSort(N: integer); var B: array [1 .. n] of integer; i, j: integer; begin for i:=0 to N do begin j:=i; while (j>1) and (B[j-1]>A[i]) do begin
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c 00-99 count.c

#include unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66, 0x6d,0x7d,0x07,0x7f,0x6f}; unsigned char Count; void delay10ms(void) { unsigned
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c state.c

#include void main(void) { while(1) { if(P1_4==0) { P1_0=0; } else { P1_0=1; }
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c key-press.c

#include unsigned char count; void delay10ms(void) { unsigned char i,j; for(i=20;i>0;i--) for(j=248;j>0;j--); } void main(void) { while(1) { if(P3
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c 1.c

#include void main(void) { while(1) { if(P1_4==0) { P1_0=0; } else { P
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txt 布尔母函数.txt

//布尔母函数 //判m[]个价值为w[]的货币能否构成value //适合m[]较大w[]较小的情况 //返回布尔量 //传入货币种数n,个数m[],价值w[]和目标值value #define MAXV 100000 int genfunc(int n,int* m,int* w,int value){ int i,j,k,c; char r[MAXV]; for
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txt 最大公约数欧拉函数.txt

int gcd(int a,int b){ return b?gcd(b,a%b):a; } inline int lcm(int a,int b){ return a/gcd(a,b)*b; } //求1..n-1中与n互质的数的个数 int eular(int n){ int ret=1,i; for (i=2;i*i
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c re.c

#include main() { int n,s,j,k,p; int a[100];//最多允许100人 printf("请输入人数:"); scanf("%d",&n); printf("请输入数字:"); scanf("%d",&s); for(j=0;j
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c 十五人排序.c

/*原题: 一寝室有15个人,每天都要三人一行外出散步一次,要在一周 (7天)内 每个人都跟其他14人各散步一次,问每一天应该怎么安排?? 要快点想哟!!!! 都等一会15分钟*/ #include int anpai[7][5][3]; int biaozhi[16][16]; int i=0,j=0,k=0,a,total=0; void hui