代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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txt 求出平均分链表.txt

{ double av=0.0; STREC *p=h->next; while(p!=NULL) {av=av+p->s; p=p->next; } return av/N; }
www.eeworm.com/read/355007/10305815

c fstreql.c

int fstreql(char far *str1, char far *str2) { while ((*str1 == *str2) && (*str1)) { str1++; str2++; } return((*str1 == NULL) && (*str2 == NULL)); }
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src token.src

/* ** token.src - String parser for KEYWORDS. ** (C) Copyright 1990-1998 by Aptech Systems, Inc. ** All Rights Reserved. ** ** This Software Product is PROPRIETARY SOURCE CODE OF APTECH ** SYSTE
www.eeworm.com/read/162128/10333686

c fstreql.c

int fstreql(char far *str1, char far *str2) { while ((*str1 == *str2) && (*str1)) { str1++; str2++; } return((*str1 == NULL) && (*str2 == NULL)); }
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c gf.c

#include #include #include #define uchar unsigned char #define uint unsigned int #define _RDY_ 0x06 #define _BUSY_ 0x15 #define _OK_ 0x00 #define _SUCC_ 0x0
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cpp noname03.cpp

#include #include #include //#define seed 56 void r1(); void r3(); void r2(); void r4(); void f1(); void f2(); void f4(); void f3(); int seed,r
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m reduce.m

function s = reduce(p); s = cell(length(p),1); for i = 1:length(p) s{i} = i; end while size(s) > 2 [p,i] = sort(p); p(2) = p(1) + p(2); p(1) = []; s = s(i); s{2} = {s
www.eeworm.com/read/161929/10356530

cpp sort.cpp

#include using namespace std; //直接顺序排序 void InsertSort(int r[], int n) { for (int i=2; i
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cpp seqsearch.cpp

int SeqSearch1(int r[], int n, int k){ r[0]=k ; //设置哨兵 int i=n; while (r[i]!=k) //若r[i]与k相等,则返回当前i的值;否则继续比较前一个记录; i--; return i; }
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cpp sort.cpp

#include using namespace std; //直接顺序排序 void InsertSort(int r[], int n) { for (int i=2; i