代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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c gc.c

/* 22nov07abu * (c) Software Lab. Alexander Burger */ #include "pico.h" /* Mark data */ static void mark(any x) { cell *p; while (num((p = cellPtr(x))->cdr) & 1) { *(word*)&cdr(p) &=
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_shift

#!/bin/sh while [ "$1" != "" ]; do echo "$1" shift done exit 0
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cpp graph3.cpp

//图的运算的实现文件graph3.cpp #include"graph3.h" //构造函数,初始化图的邻接矩阵与边集数组 adjMList::adjMList(RCW GE[],int n,int e) {int i,j; for(i=0; i
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txt 21-30.txt

【程序21】 题目:猴子吃桃问题:猴子第一天摘下若干个桃子,当即吃了一半,还不瘾,又多吃了一个    第二天早上又将剩下的桃子吃掉一半,又多吃了一个。以后每天早上都吃了前一天剩下    的一半零一个。到第10天早上想再吃时,见只剩下一个桃子了。求第一天共摘了多少。 1.程序分析:采取逆向思维的方法,从后往前推断。 2.程序源代码: main() { int day,x1,x2; ...
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c 2.c

#include sbit K1=P3^0; sbit L1=P1^0; void main(void) { while(1) { if(K1==0) { L1=0; //灯亮 } else { L1=1; /
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c 8.c

#include sbit P3_7=P3^7; unsigned char count; void delay10ms(void) { unsigned char i,j; for(i=20;i>0;i--) for(j=248;j>0;j--); } void main(void) { while(1) {
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c 12.c

#include sbit P3_6=P3^6; sbit P3_7=P3^7; unsigned char curcount; void delay10ms(void) { unsigned char i,j; for(i=20;i>0;i--) for(j=248;j>0;j--); } void main(void) {
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c 10.c

#include sbit P3_7=P3^7; unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66, 0x6d,0x7d,0x07,0x7f,0x6f}; unsigned char Count; void delay10ms(void) {
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c test3.c

PROGRAM boucleinfinie VAR i; i := 1; WHILE 1=1 DO BEGIN PRINT i; i := i+1; END
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cpp sort.cpp

/* Copyright (C) 1999 Lucent Technologies */ /* From 'Programming Pearls' by Jon Bentley */ /* sort.cpp -- test and time sorting algorithms Input lines: algnum n mod Output lines: algnum n mod