代码搜索:while

找到约 10,000 项符合「while」的源代码

代码结果 10,000
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bak 找最小公倍数.bak

input"输入M:" to m input"输入N" to n a=m b=n if n=0 then ?"数据有错!" exit endif r=mod(m,n) do while r>0 m=n n=r r=mod(m,n) enddo ?"最大公约数是:",n ?"最小公倍数是:",a*b/n
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prg 找最小公倍数.prg

input"输入M:" to m input"输入N" to n a=m b=n if n=0 then ?"数据有错!" exit endif r=mod(m,n) do while r>0 m=n n=r r=mod(m,n) enddo ?"最大公约数是:",n ?"最小公倍数是:",a*b/n
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prg 找最大公约数.prg

input"输入M:" to m input"输入N" to n if n=0 then ?"数据有错!" exit endif r=mod(m,n) do while r>0 m=n n=r r=mod(m,n) enddo ?"最大公约数是:",n
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c 3rabs.c

void rabs(a,b,r,p,n) int a,b,*r,n,p[]; { int k,l,m,i; k=b-a+1; l=2; while (l
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c 3rabs.c

void rabs(a,b,r,p,n) int a,b,*r,n,p[]; { int k,l,m,i; k=b-a+1; l=2; while (l
www.eeworm.com/read/246953/12695880

c ex4-22.c

#include main() { int x, *p, ** q; x=10; p=&x; q=&p; printf("%d\n:, x); printf("%d\n:, * p); printf("%d\n:, ** q); while(1);
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m ex0108.m

function ex0108() n = 1; a=[9 2 4 3 5 6 8 0]; min=inf; while n
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m pos_retmin1.m

function [p,i]=pos_retmin1(X) n=length(X); m=1; q=0; while m
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tny test2.tny

{this is an example} int A,B; bool C; char D; D:='scanner'; C:=A and not B; while A
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txt ch8_2.txt

void binsort(JD r[],int n) { int i,j,x,s,m,k; for(i=2;i