代码搜索:utils
找到约 10,000 项符合「utils」的源代码
代码结果 10,000
www.eeworm.com/read/417049/11005353
h utils.h
#ifndef UTILS_H_DEFINED
#define UTILS_H_DEFINED
#include
#define UNKNOWN 0x00
#define NO 0x00
#define YES 0x01
#define TYPE_STRING 1
#define TYPE_INT 2
www.eeworm.com/read/270995/11013177
c utils.c
#include
#include
#include
#include "utils.h"
void strcreate(char **dest, char *src) {
*dest = (char *)malloc(sizeof(char) * strlen(src) + 1);
if (!*dest) {
s
www.eeworm.com/read/270995/11013194
h utils.h
#ifndef _UTILS_H
#define _UTILS_H
void strcreate(char **dest, char *src);
void syserror(char *loc);
void error(char *loc, char *message);
int flip(double prob);
double randFraction(void);
i
www.eeworm.com/read/270993/11013532
c utils.c
#include
#include "const.h"
#include "type.h"
#include "extern.h"
#include "exfunc.h"
int erfunc(char *s, int val)
{
fprintf(stderr, "%s %d\n", s, val);
exit(1);
}
void struct_cp(to, f
www.eeworm.com/read/416638/11018887
java utils.java
import java.io.UnsupportedEncodingException;
/**
* @author LJ-silver
*/
public class Utils {
/**
* 从ip的字符串形式得到字节数组形式
* @param ip 字符串形式的ip
* @return 字节数组形式的ip
*/
www.eeworm.com/read/416594/11020088
h utils.h
#ifndef __UTILS_H
#define __UTILS_H
void memcpy(void *s1, const void *s2, int n);
void memset(void *s, const char ch, int n);
unsigned short ntohs(unsigned short s);
unsigned long ntohl(unsigne
www.eeworm.com/read/416594/11020095
o utils.o
www.eeworm.com/read/416594/11020141
c utils.c
#include "../inc/def.h"
#include "../inc/board.h"
#include "../inc/utils.h"
void memcpy(void *s1, const void *s2, int n)
{
int i;
for (i = 0; i < n; i++)
((char *)(s1))[i] = ((const cha
www.eeworm.com/read/270376/11040836
c utils.c
/* General utility routines for the remote server for GDB.
Copyright (C) 1986, 1989, 1993 Free Software Foundation, Inc.
This file is part of GDB.
This program is free software; you can redistrib
www.eeworm.com/read/470209/6915229
c utils.c
#include "tdestr.h"
#include "common.h"
#include "define.h"
#include "tdefunc.h"
/*
* Name: myiswhitespc
* Purpose: To determine whether or not a character is *NOT* part of a "word"