代码搜索：until
找到约 4,232 项符合「until」的源代码
代码结果 4,232
www.eeworm.com/read/184327/9109909
pas ac1013.pas
program tju1013;
var
s:string;
n,m,i,j,p,q:byte;
c:char;
begin
repeat
s:='';
repeat
read(c);
if c=' ' then break;
s:=s+c;
until false;
n:=length(
www.eeworm.com/read/184327/9109957
pas ac1076.pas
program tju1076;
const
m=7;
var
f:array[0..m*m+1]of byte;
p:array[0..m-1,0..m-1]of longint;
a,b,n,i,t:longint;
begin
f[1]:=1;f[2]:=1;
repeat
read(a,b,n);
if n=0 then hal
www.eeworm.com/read/380452/9148237
c dz60_init.c
/*******************************************************************************/
/*
Copyright (c) 2007 Freescale Semiconductor
Freescale Confidential Proprietary
\file DZ60_init.c
\brief
www.eeworm.com/read/378832/9214998
c ssp.c
/*****************************************************************************
* ssp.c: SSP C file for Philips LPC214x Family Microprocessors
*
* Copyright(C) 2006, Philips Semiconductor
www.eeworm.com/read/376846/9303698
txt 05.txt
var a,sum;
begin
sum:=0;
a:=1;
repeat
sum+=a;
a++;
until a>100;
write(sum);
end.
www.eeworm.com/read/164696/10094887
c ssp.c
/*****************************************************************************
* ssp.c: SSP C file for Philips LPC214x Family Microprocessors
*
* Copyright(C) 2006, Philips Semiconductor
www.eeworm.com/read/162188/10327652
src waitc.src
/*
** waitc.src
** (C) Copyright 1988-1998 by Aptech Systems, Inc.
** All Rights Reserved.
**
** This Software Product is PROPRIETARY SOURCE CODE OF APTECH
** SYSTEMS, INC. This File Header m
www.eeworm.com/read/353766/10419298
c dz60_init.c
/*******************************************************************************/
/*
Copyright (c) 2008 Freescale Semiconductor
Freescale Confidential Proprietary
\file DZ60_init.c
\brief
www.eeworm.com/read/353224/10461578
c ssp.c
/*****************************************************************************
* ssp.c: SSP C file for Philips LPC214x Family Microprocessors
*
* Copyright(C) 2006, Philips Semiconductor
www.eeworm.com/read/468916/6981835
tny sample.tny
int A,B,C,D;
while AD do
if A=1 then A:= B*C+37
else repeat A: