代码搜索:sparse

找到约 3,324 项符合「sparse」的源代码

代码结果 3,324
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sparse

Puzzle 1347772720 16 16 IVVVIVIVIIVIIIIIIIIIVIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIVIVVIIIIIIIIVIIIIVIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIVVIVIIIIVVVIIVIIIIVIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIVII
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sparse arcs

Electrify 1279877491 1.85 inches 1279877484 3.90 inches 1279882344 29.000 1279879777 90.000 1279877746 75.000 1279877747 33.000 1279881830 1 1382966355 3586 1279879031 88.000 1332765556 22.0
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at sparse02.at

# Process this file with autom4te to create testsuite. -*- Autotest -*- # Test suite for GNU tar. # Copyright (C) 2004, 2006, 2007 Free Software Foundation, Inc. # This program is free software; you
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at sparse01.at

# Process this file with autom4te to create testsuite. -*- Autotest -*- # Test suite for GNU tar. # Copyright (C) 2004, 2006, 2007 Free Software Foundation, Inc. # This program is free software; you
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at sparse03.at

# Process this file with autom4te to create testsuite. -*- Autotest -*- # Test suite for GNU tar. # Copyright (C) 2005, 2006, 2007 Free Software Foundation, Inc. # This program is free software; you
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texi sparse.texi

@c This is part of the paxutils manual. @c Copyright (C) 2006 Free Software Foundation, Inc. @c This file is distributed under GFDL 1.1 or any later version @c published by the Free Software Foundatio
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c sparse.c

/* Functions for dealing with sparse files Copyright (C) 2003, 2004, 2005, 2006, 2007 Free Software Foundation, Inc. This program is free software; you can redistribute it and/or modify it
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txt sparse.txt

procedure SPARSE(B:array of real; N:integer;var X:array of real; RSQ:real); label 1; const NMAX = 500; EPS = 0.000001; var G,H,XI,XJ:array[0..500] of real; J,ITER,IRST:integer;
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txt sparse.txt

procedure SPARSE(B:array of real; N:integer;var X:array of real; RSQ:real); label 1; const NMAX = 500; EPS = 0.000001; var G,H,XI,XJ:array[0..500] of real; J,ITER,IRST:integer;
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cpp sparse.cpp

void sparse(double b[], int n, double x[], double rsq) { const int nmax = 500; double eps2,eps = 0.000001; double g[500], h[500], xi[500], xj[500]; int j; eps2 = n * pow(eps, 2)