代码搜索：source
找到约 10,000 项符合「source」的源代码
代码结果 10,000
www.eeworm.com/read/239407/13281493
lck s7source.lck
www.eeworm.com/read/137419/13322894
bak source_uv2.bak
### uVision2 Project, (C) Keil Software
### Do not modify !
Target (Target 1), 0x0000 // Tools: 'MCS-51'
Group (Source Group 1)
File 1,1,
File 1,2,
www.eeworm.com/read/323313/13344031
txt event_key_source.txt
黄菊，男，汉族，１９３８年９月生，浙江嘉善人，１９６６年３月加入中国共产党，１９６３年５月参加工作，清华大学电机工程系电机制造专业毕业，大学学历，工程师。
现年82岁的杨振宁将于明年1月与28岁在读研究生翁帆结婚。
英国一位现年51岁的妇女日前向媒体首次披露，称自己已经和“基地”组织头目拉登的第4个儿子结婚。
李湘与李厚霖离婚的消息多少让人觉得惋惜，而两人离婚后财产分配也颇受关注。
20 ...
www.eeworm.com/read/323119/13354128
sql mysql_delimiter_source.sql
delimiter //
create table t2 (a int) //
delimiter ;
\d //
create table t3 (a int) //
\d ;
show tables;
drop table t2, t3;
www.eeworm.com/read/136685/13366103
m source08025_1.m
function TU=source08025_1(T0,N0,K)
t=linspace(0,K*T0,K*N0+1);
N=length(t);
u1=t(1:(N0+1)).^2;
u2=(t((N0+2):(2*N0+1))-2*T0).^2;
u3(1:(N-(2*N0+2)+1))=0;
u=[u1,u2,u3];
TU=[t',u'];
www.eeworm.com/read/136685/13366296
m source0825_1.m
function TU=source0825_1(T0,N0,K)
t=linspace(0,K*T0,K*N0+1);
N=length(t);
u1=t(1:(N0+1)).^2;
u2=(t((N0+2):(2*N0+1))-2*T0).^2;
u3(1:(N-(2*N0+2)+1))=0;
u=[u1,u2,u3];
TU=[t',u'];
www.eeworm.com/read/322595/13375724
mdl test_source1.mdl
Model {
Name "test_source1"
Version 5.1
SaveDefaultBlockParams on
SampleTimeColors off
LibraryLinkDisplay "none"
WideLines off
ShowLineDimensions off
ShowPortD
www.eeworm.com/read/319871/13441115
m source925_1.m
function TU=source925_1(T0,N0,K)
t=linspace(0,K*T0,K*N0+1);
N=length(t);
u1=t(1:(N0+1)).^2;
u2=(t((N0+2):(2*N0+1))-2*T0).^2;
u3(1:(N-(2*N0+2)+1))=0;
u=[u1,u2,u3];
TU=[t',u'];
www.eeworm.com/read/319335/13453545
m source08025_1.m
function TU=source08025_1(T0,N0,K)
t=linspace(0,K*T0,K*N0+1);
N=length(t);
u1=t(1:(N0+1)).^2;
u2=(t((N0+2):(2*N0+1))-2*T0).^2;
u3(1:(N-(2*N0+2)+1))=0;
u=[u1,u2,u3];
TU=[t',u'];
www.eeworm.com/read/319335/13453655
m source0825_1.m
function TU=source0825_1(T0,N0,K)
t=linspace(0,K*T0,K*N0+1);
N=length(t);
u1=t(1:(N0+1)).^2;
u2=(t((N0+2):(2*N0+1))-2*T0).^2;
u3(1:(N-(2*N0+2)+1))=0;
u=[u1,u2,u3];
TU=[t',u'];