代码搜索：reverse
找到约 4,015 项符合「reverse」的源代码
代码结果 4,015
www.eeworm.com/read/301600/3837563
java beamsniper.java
package netwar.game.unit;
import java.awt.Color;
import netwar.game.*;
import netwar.game.projectile.Laser;
import netwar.utils.Trig;
import netwar.utils.vectorgraphics.*;
/** Reverse jointed
www.eeworm.com/read/301600/3837564
java lmghunter.java
package netwar.game.unit;
import java.awt.Color;
import netwar.game.*;
import netwar.game.projectile.Laser;
import netwar.utils.Trig;
import netwar.utils.vectorgraphics.*;
/** Reverse jointed
www.eeworm.com/read/273665/4199966
exp getpwuid.exp
#
# @(#) Test reverse lookup of user ids from getent match getpwuid() output
#
load_lib util-defs.exp
# Compile getpwuid.c
set output [target_compile "$srcdir/$subdir/getpwuid.c" \
"$srcdir
www.eeworm.com/read/273665/4201059
unpatch-source
#!/bin/sh -e
#
#
# We want to reverse the patches in the opposite order we applied
# them, hence the 'ls|sort -r'.
for patch in `ls debian/patches/*.patch | sort -r`; do
patch -p1 -R --ignore-whites
www.eeworm.com/read/273665/4201140
unpatch-source
#!/bin/sh -e
#
#
# We want to reverse the patches in the opposite order we applied
# them, hence the 'ls|sort -r'.
for patch in `ls debian/patches/*.patch | sort -r`; do
patch -p1 -R --ignore-whites
www.eeworm.com/read/273665/4201234
unpatch-source
#!/bin/sh -e
#
#
# We want to reverse the patches in the opposite order we applied
# them, hence the 'ls|sort -r'.
for patch in `ls debian/patches/*.patch | sort -r`; do
patch -p1 -R --ignore-whites
www.eeworm.com/read/365918/2894342
txt 维勒斯.txt
第一题：
declare
i int;
--k int;
--j int;
begin
i := 0;
for i in 1..4 loop --上四行
for k in reverse 0..(4-i) loop --打印空格
www.eeworm.com/read/359056/2980084
cpp 1218.cpp
#include
bool reverse(bool a)
{
if(a)
return false;
else
return true;
}
int getNum(int n, bool *a)
{
int count = 0;
for(int i = 1; i < n+1; i++)
{
int j = 1;
www.eeworm.com/read/147186/12579114
m assignedgenums.m
function [edge_id, nedges] = assignEdgeNums(adj_mat)
% give each edge a unique number
% we number (i,j) for j>i first, in row, column order.
% Then we number the reverse links
nnodes = length(ad
www.eeworm.com/read/201037/15417955
cpp exam.cpp
#include
class Student
{
private:
long number;
char name[10];
char sex[3];
int age;
};
typedef int DataType;
void Reverse2(int n, DataType a[])
{
int i, m = n/2;