代码搜索:reverse

找到约 4,015 项符合「reverse」的源代码

代码结果 4,015
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sh t15.sh

echo enter a num read num rev=0; while [ $num -gt 0 ] do r=`expr $num % 10` rev=`expr $rev \* 10 + $r` num=`expr $num / 10` done echo reverse is : $rev
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cpp contiguous.cpp

#include "testsuite.h" #include BZ_USING_NAMESPACE(blitz) int main() { { Array A(7,11); BZTEST(A.isStorageContiguous()); BZTEST(!(A(Range(fromStart,
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java buffertest3.java

import javax.swing.*; class BufferTest3 { public static void main(String[] args) { //自动产生 String s = JOptionPane.showInputDialog(null,"输入一个字符串:", "例子 5.3.2",JOptionPane.QUESTION_MESSAG
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c krx30600.c

/* EX3_6.C ======= Suggested solution to Exercise 3-6 */ #include #include void itoa(int n, char s[], int width); void reverse(char s[]); int main(v
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c krx51400.c

/* K&R Exercise 5-14 */ /* Steven Huang */ #include #include #include #define TRUE 1 #define FALSE 0 #define MAXLINES 5000 /* maximum number of lines
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c krx30500.c

/* EX3_5.C ======= Suggested solution to Exercise 3-5 */ #include #include void itob(int n, char s[], int b); void reverse(char s[]); in
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m flipx.m

state=get(gca,'xdir'); if(strcmp(state,'normal')) set(gca,'xdir','reverse') else set(gca,'xdir','normal') end
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m flipy.m

state=get(gca,'ydir'); if(strcmp(state,'normal')) set(gca,'ydir','reverse') else set(gca,'ydir','normal') end
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cpp reviter4.cpp

/* The following code example is taken from the book * "The C++ Standard Library - A Tutorial and Reference" * by Nicolai M. Josuttis, Addison-Wesley, 1999 * * (C) Copyright Nicolai M. Josutti
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