代码搜索：recursive
找到约 2,177 项符合「recursive」的源代码
代码结果 2,177
www.eeworm.com/read/183626/9147160
f90 ex0828.f90
program ex0828
implicit none
integer :: n
integer, external :: fact
write(*,*) 'N='
read(*,*) n
write(*, "(I2,'! = ',I8)" ) n, fact(n)
stop
end
recursive integer function fac
www.eeworm.com/read/182385/9205464
1st 4_0read.1st
4.0 Read Me First
=================
Chapter 4 of the disc contains a simple operating system and some test programs.
The operating system does not belong to the contents of the book and is hence
www.eeworm.com/read/376037/9335812
f90 ex0828.f90
program ex0828
implicit none
integer :: n
integer, external :: fact
write(*,*) 'N='
read(*,*) n
write(*, "(I2,'! = ',I8)" ) n, fact(n)
stop
end
recursive integer function fac
www.eeworm.com/read/179087/9373436
1st 4_0read.1st
4.0 Read Me First
=================
Chapter 4 of the disc contains a simple operating system and some test programs.
The operating system does not belong to the contents of the book and is hence
www.eeworm.com/read/373348/9461893
txt 12.txt
CS 1355
Introduction to Programming in C
Thursday 2006.10.19 (Week 6)
Lecture notes (at http://r638-2.cs.nthu.edu.tw/C/notes/12.txt)
Chapter 5 continued (pp.170-179)
- Recursion
Recursion:
www.eeworm.com/read/361386/10055372
tig test39.tig
/* This is illegal, since there are two functions with the same name
in the same (consecutive) batch of mutually recursive functions.
See also test48 */
let
function g(a:int):int = a
function
www.eeworm.com/read/361386/10055381
tig test48.tig
/* This is legal. The second function "g" simply hides the first one.
Because of the intervening variable declaration, the two "g" functions
are not in the same batch of mutually recursive fun
www.eeworm.com/read/361386/10055392
tig test4.tig
/* define a recursive function */
let
/* calculate n! */
function nfactor(n: int): int =
if n = 0
then 1
else n * nfactor(n-1)
in
nfactor(10)
end
www.eeworm.com/read/361386/10055415
tig test47.tig
/* This is legal. The second type "a" simply hides the first one.
Because of the intervening variable declaration, the two "a" types
are not in the same batch of mutually recursive types.
S
www.eeworm.com/read/361386/10055431
tig test38.tig
/* This is illegal, since there are two types with the same name
in the same (consecutive) batch of mutually recursive types.
See also test47 */
let
type a = int
type a = string
in
0
end