代码搜索:println
找到约 10,000 项符合「println」的源代码
代码结果 10,000
www.eeworm.com/read/378375/9233698
java fac4_8.java
//本程序取自王晓东编著“算法分析与设计”第 139 页,例
//任务时间表问题的贪心解法
public class Fac4_8{
public static int greedyjob(int[] d,int[] w,int[] job)
{
int n=d.length-1;
d[0]=0;job[0]=0;
int k=1
www.eeworm.com/read/378375/9233724
java fac4_2.java
//
//本程序取自王晓东编著“算法分析与设计”第 113 页,例
//背包问题贪心解法
class Element implements Comparable
{
float w;
float v;
int i;
public Element(float ww,float vv,int ii)
{
www.eeworm.com/read/378375/9233768
java fac3_9_1.java
//本程序取自王晓东编著“算法分析与设计”第 96 页,例
//0-1背包问题改进动态规划解法
public class Fac3_9_1{
public static double knapsack(double []w,double []v,double c,double [][]p,int []head)
{
int n=v.length-1;
h
www.eeworm.com/read/378375/9233771
java fac3_10.java
//本程序取自王晓东编著“算法分析与设计”第 98 页,例
//最优二叉搜索树问题动态规划解法
public class Fac3_10{
public static void optimalBinarySearchTree(float []a,float []b,float[][] m,
www.eeworm.com/read/378375/9233772
java fac4_3.java
//
//本程序取自王晓东编著“算法分析与设计”第 114 页,例
//最优装载问题解法
class Element implements Comparable
{
float w;
int id;
public Element(float ww,int ii)
{
w=ww;
www.eeworm.com/read/378375/9233790
java fac5_11.java
//
//本程序取自王晓东编著“算法分析与设计”第 182 页,例
//电路板排列问题回溯解法
class Board{
static int n; //电路板数
static int m; //连接块数
static int[] x; //当前解
static int[] bestx;
www.eeworm.com/read/181552/9246155
java csmailform.java
//CSMailForm.java
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
import java.net.*;
import java.util.*;
import com.coolservlets.*;
import com.coolservlets.email.*;
pu
www.eeworm.com/read/377970/9255230
java ex3_3_2.java
public class ex3_3_2
{
int x;
public ex3_3_2(int x1){
x=x1;
}
public static void main( String args[ ] )
{
ex3_3_2 m1=new ex3_3_2(4);
ex3_3_2 m2=ne
www.eeworm.com/read/377970/9255244
java ex2_7_2.java
public class ex2_7_2
{
public static void main( String args[ ] )
{
outer:
for(int i=1;i
www.eeworm.com/read/377968/9255257
java matrix.java
public class Matrix{
public static void main(String args[]){
int i,j,p;
int a[][]={{1,2,3},{2,1,3},{3,2,1}};
int b[][]={{4,1,3},{3,1,1},{1,4,1}};
int c[][]=new int[3][3];
int d[][]=new int[3][3]