代码搜索：printf
找到约 10,000 项符合「printf」的源代码
代码结果 10,000
www.eeworm.com/read/234679/14101143
c 13kfwt0.c
#include "stdio.h"
#include "13kfwt.c"
main()
{ int i;
double p[8],x[8];
for (i=0; i
www.eeworm.com/read/132270/14102568
r018m
#include "stdio.h"
void main()
{
int i,j,k,temp,x,y;
int a[100][100];
int b[100][100];
int c[100][100];
printf("为了可同时实现矩阵的加减乘运算，请输入方阵，即矩阵的行数等于列数。\n");
printf("请输入你要计算的矩阵行(列)数:\n");
sca
www.eeworm.com/read/132119/14109480
txt 12111.txt
/*-----------------------------------------------------------------------*\
| |
| Robotics 95 -- Final Co
www.eeworm.com/read/234146/14120781
c magicmatrix.c
#include
#include
void swap(int *p1,int *p2)
{
int temp;
temp=*p1;
*p1=*p2;
*p2=temp;
}
void table(int n,int flag)
{
int i,a,b,c;
switch(flag){
www.eeworm.com/read/234146/14120812
c johnconway.c
/* Demo of John Conway life game.
*
* Written by Cyril Hu (cyrilhu@gmail.com), public domain.
*/
#include
#include
#include
#define Z 20
#define X 10
#define Y 10
int l
www.eeworm.com/read/234146/14120821
c qpl.c
/*qpl.c----n */
#define N 4
int main(void)
{ int i,j,k,t,found;
int a[N+1];
t=1;
for (k=1;k
www.eeworm.com/read/234146/14120860
c sj_4.c
int b[22];
long int count=0;
static int a[21][8];
static int s[12]={1,3,5,7,11,13,17,19,23,29,31,37};
fun(int i,int k)
{int j,flag,p;
for(j=1;a[i][j]!=0;++j)
{
flag=1;
for(p=1;p
www.eeworm.com/read/234146/14120863
c josephus.c
/* Josephus.c */
#define N 32
#include
int main(void)
{ static int a[N+1],b[N+1];
int i,j,s,m,p;
scanf("%d%d",&s,&m);
for (i=1;i