代码搜索：printf
找到约 10,000 项符合「printf」的源代码
代码结果 10,000
www.eeworm.com/read/339269/6353234
cpp branch.cpp
#include
#include
double a[10][10];
void Guass(int n){
int i,j,k;
double t;
for(k=0;k
www.eeworm.com/read/187296/6354518
c varcheck.c
# include "stdio.h"
void Swap(int *a,int *b) /*交换a,b*/
{
*a=*a^*b;
*b=*b^*a;
*a=*a^*b;
}
void main(void)
{
int i=1,j=2;
printf("i=%d,j=%d\n",i,j);
Swap(&i,&j);
printf(
www.eeworm.com/read/193359/6355412
txt 7-12.txt
/* 范例：7-12 */
#include
int main()
{
/* 数组与指针 */
char sa[] = "this is a book";
char *ptr = "this is a book";
/* 结果输出至屏幕 */
printf("这是sa数组字符串 -->%s",sa);
printf("\n这是ptr指针
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c main.c
/*
Calculate or Check MD5 Signature of File or Command Line Argument
by John Walker
http://www.fourmilab.ch/
This program is in the public domain.
*/
#define VERSION "2.2
www.eeworm.com/read/494733/6374569
txt 1.txt
【程序1】
题目：有1、2、3、4个数字，能组成多少个互不相同且无重复数字的三位数？都是多少？
1.程序分析：可填在百位、十位、个位的数字都是1、2、3、4。组成所有的排列后再去掉不满足条件的排列。
2.程序源代码：
main()
{
int i,j,k;
printf("\n");
for(i=1;i
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cpp 杭电1003.cpp
/*算法：1.一直相加直到和出现负数，在相加期间能得到一个最大和，记录
2.重复1步骤，更新最大和，直到输入完毕
原理：如果在连续子串 中Sn0时任意的 (i>1) 的和都小于0，
所以这些元素就
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cpp transport.cpp
#include
#include
#define NMAX 10
double C[NMAX][NMAX], XM[NMAX][NMAX];
double R[NMAX][NMAX];
double DAO[NMAX], RAD[NMAX];
int P[5][2*NMAX+5];
www.eeworm.com/read/494289/6381502
c williams.c
/*
* Program to factor big numbers using Williams (p+1) method.
* Works when for some prime divisor p of n, p+1 has only
* small factors.
* See "Speeding the Pollard and Elliptic Curve
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c pollard.c
/*
* Program to factor big numbers using Pollards (p-1) method.
* Works when for some prime divisor p of n, p-1 has itself
* only small factors.
* See "Speeding the Pollard and Elliptic Cu
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c hilbert.c
/*
* Solve set of linear equations involving
* a Hilbert matrix
* i.e. solves Hx=b, where b is the vector [1,1,1....1]
*
* Copyright (c) 1988-1997 Shamus Software Ltd.
*/
#include