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找到约 10,000 项符合「plot」的源代码

代码结果 10,000
www.eeworm.com/read/321385/13407790

m fig9_20.m

clear all eps = 0.0000001; npts = 5000; del = 1./ 5000.; t = 0. : del : 1.; % generate input sequence inp = 1.+ t.^3 + .5 .*t.^2 + cos(2.*pi*5 .* t) ; % read the intial estimate for the state v
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m fig9_21.m

clear all eps = 0.0000001; npts = 5000; del = 1./ 5000.; t = 0. : del : 1.; % generate input sequence inp = 1.+ t.^3 + .5 .*t.^2 + cos(2.*pi*5 .* t) ; % read the intial estimate for the state v
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m fig9_28.m

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the
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m fig9_27.m

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2);% + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurmeny vector H=[1,0,0] % this is the
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m program_6a.m

% Chapter 6 - Controlling Chaos. % Program_6a - Controlling chaos in the logistic map. % Copyright Birkhauser 2004. Stephen Lynch. % Control to a period-2 orbit (Figure 6.3(b)). clear itermax=2
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m program_2d.m

% Chapter 2 - Nonlinear Discrete Dynamical Systems. % Program 2d - Bifurcation diagram of the logistic map. % Copyright Birkhauser 2004. Stephen Lynch. % Plot a bifurcation diagram (Figure 2.15).
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m hc111.m

%《数字信号处理教程——MATLAB释义与实现》第一章例1.1.1程序hc111 % 连续信号、离散信号和数字信号 % 电子工业出版社出版 陈怀琛编著 2004年9月 % dt=0.001;t=0:dt:6; % 建立连续自变量向量 xa=sqrt(t)+cos(t); % 原始的连续时间信号xa(t) T=0.5;n=0:6/T; % T为采样周期,建立离散自变量向量
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m hc721.m

%《数字信号处理教程——MATLAB释义与实现》第七章例7.2.1程序hc721 % 幅频特性与符幅特性的区别 % 电子工业出版社出版 陈怀琛编著 2004年9月 % clear b=[-1,2,4,2,-1];a=1; % 给定滤波器系数向量 [H,w]=freqz(b,a); % 求频率特性 subplot(2,2,1),p
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m hc722.m

%《数字信号处理教程——MATLAB释义与实现》第七章例7.2.2程序hc722 % 线性相位FIR滤波器的类型及符幅特性 % 电子工业出版社出版 陈怀琛编著 2004年9月 % clear h1=[3,-1,2,-3,5,-3,2,-1,3]; % 输入一个类型I的线性相位滤波器系数 [A1,w1,typea,tao1]=amplres(h1);
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m am.m

% am.m % Matlab demonstration script for DSB-AM modulation. The message signal % is +1 for 0 < t < t0/3, -2 for t0/3 < t < 2t0/3 and zero otherwise. echo on t0=.15; % sig