代码搜索：plot
找到约 10,000 项符合「plot」的源代码
代码结果 10,000
www.eeworm.com/read/322280/13383746
m dipoleantenna_frequence.m
clear all;close all;
a=[1e-7,1e-5,1e-3];%三个天线半径
L=1;%天线长
lamda0=2;%波长为此数时,为半波天线
n=21;%段数,必须为奇数
e=8.85e-12;%介电常数
u=4e-7*pi;%磁导率
eta=120*pi;%波阻抗
delta=L/(n+1);
for m=1:3
for t=1:300
www.eeworm.com/read/321972/13391626
m fig2_6.m
x = 0:0.1:10;
y = x.^2 - 10.*x + 26;
figure(1)
subplot(2,2,1)
plot(x,y);
title ('Linear Plot');
xlabel ('x');
ylabel ('y');
grid on;
subplot(2,2,2)
semilogx(x,y);
title ('Semilog x Plot');
www.eeworm.com/read/321771/13399505
m regroutl.m
function [W] = RegrOutl(X,W)
% [W] = RegrOutl(X,W)
% [W] = RegrOutl(X)
%
% Function eliminates outliers interactively.
% Feedback is given on the graphical screen -
% mouse clicks toggle
www.eeworm.com/read/321463/13404304
m hmmdemo.m
echo on;
clc;
% load and plot data on geyser eruption durations and waiting times
load geyser;
clf;
subplot(211);
plot(geyser(:,1),g
www.eeworm.com/read/321442/13404833
m smith2.m
for r=0:10
for rr=1/(1+r);
cr=1-rr;
plot(cr+rr*cos(tr),rr*sin(tr),'m')
hold on
end
end
www.eeworm.com/read/321442/13404836
m calledit1.m
for x=-1:0.5:2;
r=1;
u=(r.^2+x.^2-1)/(r.^2+2*r+1+x.^2);
v=(2*x)/(r.^2+2*r+1+x.^2);
tr=2*pi*(0:0.01:1);
l=sqrt(u^2+v^2);
plot(l*cos(tr),l*sin(tr),'w'); axis([-1,1,-1,1]);
hold on
end
for r1=0:
www.eeworm.com/read/321424/13405120
m fig9_20.m
clear all
eps = 0.0000001;
npts = 5000;
del = 1./ 5000.;
t = 0. : del : 1.;
% generate input sequence
inp = 1.+ t.^3 + .5 .*t.^2 + cos(2.*pi*5 .* t) ;
% read the intial estimate for the state v
www.eeworm.com/read/321424/13405134
m fig9_21.m
clear all
eps = 0.0000001;
npts = 5000;
del = 1./ 5000.;
t = 0. : del : 1.;
% generate input sequence
inp = 1.+ t.^3 + .5 .*t.^2 + cos(2.*pi*5 .* t) ;
% read the intial estimate for the state v
www.eeworm.com/read/321424/13405159
m fig9_28.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurement vector H=[1,0,0]
% this is the
www.eeworm.com/read/321424/13405200
m fig9_27.m
clear all
npts = 2000;
del = 1/2000;
t = 0:del:1;
inp = (1+.2 .* t + .1 .*t.^2);% + cos(2. * pi * 2.5 .* t);
X0 = [1,.1,.01]';
% it is assumed that the measurmeny vector H=[1,0,0]
% this is the